Western Members - help my 10th grade sibling

i went all the way in to calculus in high school and i cant fucken remember this algebra problem :bang:
x=32^(1/5)

x^(5/1)= 32^[(1/5)*(5/1)]

x^5=32

i know x=2 cuz the back of the book said it and i verified with:

2*2*2*2*2
..4*4*2
....16*2
......32


but how would you do it with out knowing already that x=2
how would you solve it step by step...:huh:

shit i must have got n stupiderer to...i have no idea

is 2x6=6 ......?????
Idk... I Only went to 6th grade and got dropped 4rm skool..!! he,he,he
LMAO..!!

what more do you need to know looks like you have it down, except for maybe the fact that not too many people can do fifth roots off the top of their head. This isnt too much of a algebra problem really, more just understanding powers and roots.

i.e. X= 32^(1/5) = 5th root (32)

the reason it usually is shown as 32^(1/5) is that unless you have a program such as mathtype keyboards dont have a sqaure root sign or in this case a fifth root sign. Here is a janky looking version of the root sign, in which you would place a five in the "v" portion to denote the fifth root of something.
( \/``` )

Then the all mighty calculator come into play.

I am stupid myself, but how the fuck do you apply this shit in the real world?

i went all the way in to calculus in high school and i cant fucken remember this algebra problem :bang:
x=32^(1/5)

x^(5/1)= 32^[(1/5)*(5/1)]

x^5=32

i know x=2 cuz the back of the book said it and i verified with:

2*2*2*2*2
..4*4*2
....16*2
......32

but how would you do it with out knowing already that x=2
how would you solve it step by step...:huh:


Mrs. 2c5s says:

It means that you are taking the fifth root of 32; meaning what number is the base if the exponent is 5 and the result is 32. It's a square root problem.

Hope that makes sense.

^^^^^^^^^^^^^^^^^^^^^^^^^

She's a Algebra teacher.

what more do you need to know looks like you have it down, except for maybe the fact that not too many people can do fifth roots off the top of their head. This isnt too much of a algebra problem really, more just understanding powers and roots.

i.e. X= 32^(1/5) = 5th root (32)

the reason it usually is shown as 32^(1/5) is that unless you have a program such as mathtype keyboards dont have a sqaure root sign or in this case a fifth root sign. Here is a janky looking version of the root sign, in which you would place a five in the "v" portion to denote the fifth root of something.
( \/``` )

Then the all mighty calculator come into play.

yeah, i get that... its just that i couldnt and cant find a way to explain it ti her without already knowing the answer. hahaha

Mrs. 2c5s says:

It means that you are taking the fifth root of 32; meaning what number is the base if the exponent is 5 and the result is 32. It's a square root problem.

Hope that makes sense.
yeah i get that :emb:

thank Mrs 2c5s


its just that i didnt want her to use the calculator, i wanted her to do it free hand first

Is that in chinese?

x^5=32
what times itself 5 times = 32?


2^5 = 32 (2*2*2*2*2)


x^4= 16
what number times itself 4 times = 16?

2^4 = 16 (2*2*2*2)



when its simplified... SQUARE ROOT... x^2 = (a) ~a= whatever variable

what number times itself (2 times) = a

if a = 4 , x = 2 (square root of 4)
if a = 400 x = 20 (square root of 400)



CUBED ROOT x^3 = (a)

if a=3, x=1... Right? No... 1^3= 1*1*1 = 1 ... 1 is not = 3
So **if were staying with whole numbers**, a cannot = 3.

a=27, x=3 ... 3^3 = 27 ... Yes. (3*3*3)



Its just difficult to start thinking of things in powers over 3, because we just dont use it much. All its asking is what number, mulitplied _ times = your variable.

x= answer
y= root
a= number

x^y=a with any 2, you should be able to find the 3rd. I think in algerbra you stick with whole numbers, so you wont have (example) x^3 = 3 as it would be a decimal answer... actually i think it would be a limit (calc 1 and 2).


*=> (means is = to)

x^y=a => x^(1/x)=y
3^2=6 => 6^(1/3)=2

So you could get...
3^y=6 => 6^(1/3)= y ; y=2
or
x^2=6 => 6^(1/x)=2 ; x=3
or, the most common...
3^2=a => a^(1/3)=2 ; a=6

Therefore you know that anytime you see
a^(1/x)=y ...you should be looking to convert it to:
x^y=a ...because the calculations ae easier to comprehend.

gil you should have just called me, you know im a nerd.

X ^(1/y) = yth root of X. <--- beating a dead horse.

I am stupid myself, but how the fuck do you apply this shit in the real world?

Lmfao +1

i had to do point slope form when changing oil once :lol:

2*2*2*2*2
..4*4*2
....16*2
......32


And you were right here... just backwards.

x^5=32

32
option 1: 2*(16) (2 numbers)
2*(4*4) (3 numbers)
2*(2*2*2*2) (5 numbers) - Thats what we want!

32
option 2: (4)*(8)
(2*2)*(2*2*2)


**Note both option 1 and option 2 turned out the same.


What does this mean... It means you cannot do 32 in any other root. Why not? Because you dont have any number multiplied only by itself. (if were still using whole numbers**)

x^2= 32

32
option 1: 4*8 - no

32
option 2: 2*16 - no

------------------

x^3=32 (looking for a number multiplied by itself 3 times that equals 32)

32
option 1: 4*8
option 1a: (2*2)*8 - no
option 1b: 4*(4*2) - no

2: 2*16
2a: 2*(2*8) - no
2b: 2*(4*4) - no


There can be MANY MANY 'options'...


x^4=32 (looking for a number multiplied by itself 4 times that equals 32)

32
1: 2*2*8
(2*2)*(2*4) - not possible




But take a number like 64

x^3=64

64
4*16
4*4*4 - x=4 But wait.... Why can i reduce this further?
(2*2)*(2*2)*(2*2) - What does this mean?

it means that 2*2*2*2*2*2 = 64... or 2^6=64


try 256
16*16 - 16^2=256
(4*4)(4*4) - 4^4=256
(2*2*2*2)(2*2*2*2) - 2^8=256


What else does this tell us?

16^2=256
4^4=256
2^8=256

Well we know that: 16^2 = 4^4 = 2^8 ... right?
so x^y = square root(x)^(y)*2 = 4th root(x)^y(4)

so using x=16 , y=2

16^2 = 256

square root (16)^(2)*2 = 4^4 = 256

4th root (16)^(2)*4 = 2^8 = 256






Lets apply that to the number earlier 32 2^5 ; x^y = square root(x)^(y)*2 = quard root(x)^y(4) ... SR= square root

x=2, y=5

2^5 = 32
square root(2)^(5)*2 - not possible

BECAUSE the SR(2) is a decimal ... we are only dealing with whole numbers. So we proved again that 32 cannot have any other possible # of roots. (IE x^3 cannot = 32 , x^2 cannot =32 , because it creates decimals.)

^^ wtf??????

i quit after taking algebra 3 times :(

i have a degree in english. i cant count.

i had to do point slope form when changing oil once :lol:

LOL.. i hope your joking... if not elaborate.

LOL.. i hope your joking... if not elaborate.

i was replying to dan about using algebra in real world but joking LOL

wow some freakin smart people in here!

Yeah when I was in school for mech engineering, I couldn't give a shit about the formulas, they will always exist, haha I just knew how to solve them, it just would happen I was lookin at this going ok.... 2, didn't know why didn't care.

I guess I musta remembered something, Gil thats awesome makin her do it free hand first, these calculators are freakin ridiculous, hell when I first used em I remember programming my own formulas in them so I didn't have to remember them. Was awesome for tests just plug in and it solved it for me.

Missed this one...and I think that I'm one of handfull of people here with a degree in Mathematics...

lol yeah I know how to do these things..... k kw how to do them in the calculator also. just wanted her to think....

i bought her a laptop aswell As an encyclopedia and she has a library card. and a couple if dictionaries also. it's great that everything is going digital however I still want her to know her stuff wen the digital era forces us under ground.... to the city called Zion

Got a pic of her? :secret2:

umm 14 jose

lmao that's why I said sibling on the title... pervs lmao
shoulda continued on the thread also

Lol 14 in 10th not bad I was 17 in 10th. lol.

wow, tech has sunk to a new low. First calc, then hitting on 14 year olds. :huh: