# New LS1 Owners - Newbie Tech - I have a basic mechanic question....

99blownLS-WON
08-13-2009, 01:43 PM
I don't want to sound dumb but I have asked several peoplle this question. When a engine is a "5.7" liter or "5.0" what does the 5.7 stand for?? I have heard its the amount oil the crank case holds or the maximum amount of air a engine can hold. Can some one shine some light on me??

08-13-2009, 01:52 PM
no, its the total displacement of the engine. a 5.7 liter engine is somewhere around 5700cc, cubic centimeters. who ever has told you that is a total dipshit haha.

conan
08-13-2009, 01:54 PM
5.7 litre is the displacement of the cylinders. So a 5.7 liter is a 346 cubic inch engine.
1 litre = 61.0237441 cubic inch.

my bandit
08-13-2009, 01:56 PM
its pretty much the displacement of the engine. 5.7=346ci 6.0=400ci 5.0=302ci

its the volume covered by all the pistons on one stroke added up. thats the easiest way to explain it. the way you find it is by using the bore and stroke to figure out the ci.
its alot of math but its easy. so 1000CC=1 liter and you convert it to CI and figure it out from there. it has nothing to do with the oil

conan
08-13-2009, 01:59 PM
its pretty much the displacement of the engine. 5.7=346ci 6.0=400ci 5.0=302ci

its the volume covered by all the pistons on one stroke added up. thats the easiest way to explain it. the way you find it is by using the bore and stroke to figure out the ci.
its alot of math but its easy. so 1000CC=1 liter and you convert it to CI and figure it out from there. it has nothing to do with the oil

6.0L is 366 cubic inches
6.6L is a 400 cubic inch.

99blownLS-WON
08-13-2009, 01:59 PM
oh ok this makes alot of sense now!! so in that aspect a 5.7 liter l98 is the same 346 ci as an ls1???

my bandit
08-13-2009, 02:03 PM
6.0L is 366 cubic inches
6.6L is a 400 cubic inch.

my bad haha ive got like 3 things goin on at once. thanks for the correction

conan
08-13-2009, 02:34 PM
my bad haha ive got like 3 things goin on at once. thanks for the correction

:cheers:

TooLateVTEC
08-13-2009, 03:51 PM
oh ok this makes alot of sense now!! so in that aspect a 5.7 liter l98 is the same 346 ci as an ls1???

No, the 1st and 2nd generation 5.7 liter SBC's are actually 350 cubic inches.

the_merv
08-13-2009, 03:58 PM
6.0L is 366 cubic inches
6.6L is a 400 cubic inch.

364ci..;)

6.6l can be a 400 Small Block, 402 LS Stroker.. and probably a couple of others.

oh ok this makes alot of sense now!! so in that aspect a 5.7 liter l98 is the same 346 ci as an ls1???

Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.

IRONFIST
08-13-2009, 04:03 PM
Cubic inches is a more precise unit of measurement, liters are rounded the tenth decimal place.
That's why a 6.6L is both a 400 Pontiac, and a 403 Olds.

conan
08-13-2009, 04:17 PM
364ci..;)

6.6l can be a 400 Small Block, 402 LS Stroker.. and probably a couple of others.

Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.

Copy that :thumb:

99RTA
08-13-2009, 06:17 PM
Its really means that every complete turn of the crankshaft the engines displaces 5.7L or 346 cubic inches of space. That means the pistons move or displace that amount of space. What comes next is that space is filled with an air-fuel mixture and compressed then ignited forcing the pistons down causing the crankshaft to rotate.

08-13-2009, 06:29 PM
[/QUOTE]
Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.[/QUOTE]

yeah, but those damn douchers at ford cheater with their 5.0. :) sissy 4.9s!

the_merv
08-13-2009, 06:52 PM
Lol..the performance makes up for it..:nod:

ParkerTPIz
08-13-2009, 08:18 PM
good explanation guys, couldnt agree more :)

02WS6SSZ71
08-14-2009, 05:54 AM
In case you were curious where everyone is coming up with their displacements, its just simple math. Find the area of an individual cylinder...pi X (radius squared) X height, or in gearhead speak 3.14 X (1/2 of bore squared) X stroke. Take this number x the number of cylinders (eight if your a real man) and you have displacement. Example: engine with bore of 3.9 and stroke of 3.62.

3.14 X [(0.5 X 3.9)(0.5 X 3.9)] X 3.62 = 43.22
43.22 X 8 = 345.78, rounded to 346 = LS1

To get the displacement in metric, just use measurements in centimeters for bore and stroke.

the_merv
08-14-2009, 09:05 AM
Take this number x the number of cylinders (eight if your a real man) and you have displacement.

:lol: