Capacitor Charging Issue
06-08-2007, 09:17 PM
#1
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Capacitor Charging Issue I am running two .5 farad capacitors (1 for each amp) with my sub setup and one keeps blowing the amp fuse when I try to connect it...it is charged up and I know that its hooked up right as far as polarity is concerned so what do I need to do to get it hooked up without blowing the amp fuse so I can finally call this project complete!?
06-08-2007, 09:28 PM
#2
Do yourself a favor and don't hook it up. A .5 farad cap isn't going to help anything.
joule = 1 watt second. 5 joules = power of 5 watts in 1 second, power of 1 watt for 5 seconds, etc.
Take 1/2 the capacitor value and multiply by voltage squared to get the storage capacity your capacitor. .5/2 x (14x14) = 49 joules. At 11 volts it would store 30.25 joules. At 11 volts an Optima yellow top battery stores 2,574,000 joules. 30 on top of 2.5 million... wow, big help there!
There is MUCH more behind this, but I hope that little bit of information shows how worthless caps are.
joule = 1 watt second. 5 joules = power of 5 watts in 1 second, power of 1 watt for 5 seconds, etc.
Take 1/2 the capacitor value and multiply by voltage squared to get the storage capacity your capacitor. .5/2 x (14x14) = 49 joules. At 11 volts it would store 30.25 joules. At 11 volts an Optima yellow top battery stores 2,574,000 joules. 30 on top of 2.5 million... wow, big help there!
There is MUCH more behind this, but I hope that little bit of information shows how worthless caps are.
06-08-2007, 09:32 PM
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Originally Posted by 95bat
Do yourself a favor and don't hook it up. A .5 farad cap isn't going to help anything.
joule = 1 watt second. 5 joules = power of 5 watts in 1 second, power of 1 watt for 5 seconds, etc.
Take 1/2 the capacitor value and multiply by voltage squared to get the storage capacity your capacitor. .5/2 x (14x14) = 49 joules. At 11 volts it would store 30.25 joules. At 11 volts an Optima yellow top battery stores 2,574,000 joules. 30 on top of 2.5 million... wow, big help there!
There is MUCH more behind this, but I hope that little bit of information shows how worthless caps are.
joule = 1 watt second. 5 joules = power of 5 watts in 1 second, power of 1 watt for 5 seconds, etc.
Take 1/2 the capacitor value and multiply by voltage squared to get the storage capacity your capacitor. .5/2 x (14x14) = 49 joules. At 11 volts it would store 30.25 joules. At 11 volts an Optima yellow top battery stores 2,574,000 joules. 30 on top of 2.5 million... wow, big help there!
There is MUCH more behind this, but I hope that little bit of information shows how worthless caps are.
06-08-2007, 09:51 PM
#4
haha it might hurt more than you'd think 
But I'm sure your stereo will survive.
Have you tried disconnecting the battery when you hook up the cap?
When you hook it up, are there pops and sparks? You should be able to disconnect the battery and hook the cap up inline with the power wire. There is an "inlet" and "outlet" to the cap. One side accepts the charge from the battery, the other side you run to the amp.
But I'm sure your stereo will survive.Have you tried disconnecting the battery when you hook up the cap?
When you hook it up, are there pops and sparks? You should be able to disconnect the battery and hook the cap up inline with the power wire. There is an "inlet" and "outlet" to the cap. One side accepts the charge from the battery, the other side you run to the amp.
06-08-2007, 10:25 PM
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Originally Posted by 95bat
haha it might hurt more than you'd think But I'm sure your stereo will survive.
Have you tried disconnecting the battery when you hook up the cap?
When you hook it up, are there pops and sparks? You should be able to disconnect the battery and hook the cap up inline with the power wire. There is an "inlet" and "outlet" to the cap. One side accepts the charge from the battery, the other side you run to the amp.
But I'm sure your stereo will survive.Have you tried disconnecting the battery when you hook up the cap?
When you hook it up, are there pops and sparks? You should be able to disconnect the battery and hook the cap up inline with the power wire. There is an "inlet" and "outlet" to the cap. One side accepts the charge from the battery, the other side you run to the amp.
06-08-2007, 10:44 PM
#6
Disconnect the battery, then try. If yours only has one positive and one negative terminal then it looks like you know how to hook it up already.
Any time you mess with power wires you should always disconnect the battery though.
Any time you mess with power wires you should always disconnect the battery though.
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06-10-2007, 03:51 PM
#12
Originally Posted by HowellSoccer88
I am running two .5 farad capacitors (1 for each amp) with my sub setup and one keeps blowing the amp fuse when I try to connect it...it is charged up and I know that its hooked up right as far as polarity is concerned so what do I need to do to get it hooked up without blowing the amp fuse so I can finally call this project complete!?
