True or False: As power increases, weight reduction means MORE?
Take a stock F-Body:
Approx 3500 lbs with driver.
Approx 350 flywheel horsepower.
10 lbs to every 1 horsepower.
Approx 10 hp to drop .1 in the ¼.
3500:360 = 9.72:1
9.72:1 = 3402:350
At that point, dropping 98 lbs is the equivalent of a gain of 10 bhp.
Now add heads/cam/nitrous to the same car:
3500 lbs
600 bhp
5.83 lbs to every 1 bhp.
3500:610 = 5.74:1
5.74:1 = 3444:600
Now dropping only 66 lbs is the equivalent of a gain of 10 bhp
Please feel free to critique my reasoning. After all, it is a question, not a claim.
It takes 4X the power to accelerate a 4000 lb car the same speed as a 2000 lb car. for every time you double the weight you need 4 times the power to keep it accelerating at the same speed. somthing like that I learned in math class, I hope that made sence because I am very tired.
If you add 50 horsepower to a street bike itll pick up the kind of gains 150-200 hp will on a car....so yes...weight means more.......
If a car has 1000hp, 100 lbs will benefit alot equal to a bunch of hp gain
but a weaker engined car will get more gain from it than a high power car. when i bracket raced my little 84 cavy i went with teh car all stock and everything in it and it ran 19.9's. next time i went the weather was about the same and the car ran 19.6's. teh only difference was the jack and spare and a few other loose things in teh car had been removed. prolly not even 100lbs of stuff accounted for nearly 3tenths and 2mph of trap speed.
either way, to generate trap speed you are going for a better power to weight ration. work on whichever side of the ratio you can afford and you will make gains :burnout:
later
tim



