Does 10% increase in CI= 10% increase in HP/TQ?
Does 10% increase in CI= 10% increase in HP/TQ? Does 10% increase in CI= 10% increase in HP/TQ? If a 346 motor produced 450rwhp, if you added 34.6 cubic inches (10%), would the motor produce 10% more HP/TQ? If so, when do "diminishing returns" occur?
Does 20% more CI= 20% more HP/TQ?
Does 30% more CI= 30% more HP/TQ?
Does 40% more CI= 40% more HP/TQ?
Does 20% more CI= 20% more HP/TQ?
Does 30% more CI= 30% more HP/TQ?
Does 40% more CI= 40% more HP/TQ?
TECH Fanatic
Joined: Jun 2002
Posts: 1,979
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From: Upstate NY
Originally Posted by SPANKY LS1
Does 10% increase in CI= 10% increase in HP/TQ? If a 346 motor produced 450rwhp, if you added 34.6 cubic inches (10%), would the motor produce 10% more HP/TQ? If so, when do "diminishing returns" occur?
Does 20% more CI= 20% more HP/TQ?
Does 30% more CI= 30% more HP/TQ?
Does 40% more CI= 40% more HP/TQ?
Does 20% more CI= 20% more HP/TQ?
Does 30% more CI= 30% more HP/TQ?
Does 40% more CI= 40% more HP/TQ?
Diminishing returns on displacement/power probably occurs when you can't get enough valve area for the required airflow because you are limited by bore diameter. In other words, the architecture of the engine is the effective limiting factor.
40% increase of displacement on a 346 would be 484. It's probably not very practical to go that big on the LS1 architecture. On the other hand, a BBC can easily get there, and with available heads it would probably produce more torque and power than a 484 LS1, and for a lot less money.
A BBC with 4.5 bore and 3.8 stroke is a 484. If you could get a 4.15 bore in an LS1, you'd need a 4.47 inch stroke to get 484. No way you are going to get 2.25 intake valves in that bore like you can in the 484 BBC. The 4.47 stroke will also limit max practical rpm to 6500 or so where the 3.8 stroke engine could go to 7700 with the same average piston speed.
My $.02
