Not much help else where, plug wire resistence..
Originally Posted by technical
Because the voltage drop is now greater at the plug and there is less of a drop through the wires.
Think of a lamp. There is no break in the circuit but the lightbulb's filament isn't a great conductor. I gives off heat because of the resistance. Now skin the power cord to the point it becomes resistive, the lightbulb will dim. The high Ohm plug wires are like the skinned power cord. Drop the resistance and the lightbulb (spark plug) glows brighter, but at the expense of longevity. The ignition "circuit" actually has a break.. the plug itself between the electrodes. This is where the last voltage drop occurs. If that is the largest delta in the circuit, then the it will also be the hottest and the first to wear out.
Sorry if I don't explain myself well.
Think of a lamp. There is no break in the circuit but the lightbulb's filament isn't a great conductor. I gives off heat because of the resistance. Now skin the power cord to the point it becomes resistive, the lightbulb will dim. The high Ohm plug wires are like the skinned power cord. Drop the resistance and the lightbulb (spark plug) glows brighter, but at the expense of longevity. The ignition "circuit" actually has a break.. the plug itself between the electrodes. This is where the last voltage drop occurs. If that is the largest delta in the circuit, then the it will also be the hottest and the first to wear out.
Sorry if I don't explain myself well.
TECH Addict
Joined: Mar 2004
Posts: 2,336
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From: Fat Chance Hotel
Originally Posted by treyZ28
I think i misunderstood what you were saying (or at least I hope!)
lets say the wire with high R gained X values of heat
and the low R gained zero
the plug with wire high R gains heat Y
with low R, it wont be Y+X, just greater than Y.
I was reading your original statement to mean X +Y
lets say the wire with high R gained X values of heat
and the low R gained zero
the plug with wire high R gains heat Y
with low R, it wont be Y+X, just greater than Y.
I was reading your original statement to mean X +Y
More power (electricity) reaches the plug with low Z wires. Less resistance on the wire, more power throughput, less voltage drop, less heat dissipation *on the wire*. This means more heat will be generated at the tip of the electrode when it jumps the air gap and take more electrons from the electrode causing it to wear faster.
TECH Addict
Joined: Mar 2004
Posts: 2,336
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From: Fat Chance Hotel
Originally Posted by digitalsolo
That's not necessarily true. There are more components then the plugs and wires in the ignition circuit. Lower resistance wires could also require less energy from the coils to output x amount of power for spark at the plug. Less energy required at coils means more efficient power conversion and a cooling running coil.