6.0l ??
6.0l ?? hey guys i was just wondering what a 6.0L LQ4 or LQ9 block bored .30 or .40 over would be cubic inch wise? and is boring .40 too much? also im kinda new to these engines. how do you make the 408?
I'm building a stroker right now. To find out cubes for an engine its..
Bore x Bore X stroke x .7854 x Amount of cylinders
Eg. 4.030x4.030x4.0x.7854= 51.02 x 8= 408.18CID
So im running a 6.0L board .030 and a 4" long stroke. Hope that helps a lil.
Bore x Bore X stroke x .7854 x Amount of cylinders
Eg. 4.030x4.030x4.0x.7854= 51.02 x 8= 408.18CID
So im running a 6.0L board .030 and a 4" long stroke. Hope that helps a lil.
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Not to be an ***, but this is middle school level math. Here's the basic equation for finding the volume of a cylinder.
Eq 1) area_of_circle*height*multiplier = volume_of_cylinder(s)
Where:
Therefore,
Eq 2) pi*(bore/2)^2*stroke*number_of_cylinders = displacement
The .7854 is a mathematical factor that accounts for using bore*bore instead of pi*(bore/2)^2.
Eq 1) area_of_circle*height*multiplier = volume_of_cylinder(s)
Where:
- area_of_circle is the area of the piston [top] = pi(bore/2)^2
- height is the stroke
- multiplier is the number of cylinders
Therefore,
Eq 2) pi*(bore/2)^2*stroke*number_of_cylinders = displacement
The .7854 is a mathematical factor that accounts for using bore*bore instead of pi*(bore/2)^2.
oh okay thanks. i didnt know all that until just now. never really asked. and how much more does a forged 370 weigh compared to a cast 370? i mean internals of them.
