6.0l ??
11-22-2007, 10:07 AM
#6
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I'm building a stroker right now. To find out cubes for an engine its..
Bore x Bore X stroke x .7854 x Amount of cylinders
Eg. 4.030x4.030x4.0x.7854= 51.02 x 8= 408.18CID
So im running a 6.0L board .030 and a 4" long stroke. Hope that helps a lil.
Bore x Bore X stroke x .7854 x Amount of cylinders
Eg. 4.030x4.030x4.0x.7854= 51.02 x 8= 408.18CID
So im running a 6.0L board .030 and a 4" long stroke. Hope that helps a lil.
11-22-2007, 06:15 PM
#10
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Not to be an ***, but this is middle school level math. Here's the basic equation for finding the volume of a cylinder.
Eq 1) area_of_circle*height*multiplier = volume_of_cylinder(s)
Where:
Therefore,
Eq 2) pi*(bore/2)^2*stroke*number_of_cylinders = displacement
The .7854 is a mathematical factor that accounts for using bore*bore instead of pi*(bore/2)^2.
Eq 1) area_of_circle*height*multiplier = volume_of_cylinder(s)
Where:
- area_of_circle is the area of the piston [top] = pi(bore/2)^2
- height is the stroke
- multiplier is the number of cylinders
Therefore,
Eq 2) pi*(bore/2)^2*stroke*number_of_cylinders = displacement
The .7854 is a mathematical factor that accounts for using bore*bore instead of pi*(bore/2)^2.
12-11-2007, 11:52 PM
#15
if the weight was diff it wouldn't be enough to notice any how unless ur going for all out racing then i would use billet but they have a tendency to stretch after a while
