why so much torque w/nitrous, you ask?!
Thread Starter
On The Tree
Joined: Jan 2002
Posts: 120
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From: Aloha, Oregon
why so much torque w/nitrous, you ask?! i get a lot of raised eyebrows when i show people my dyno slips. it is really quite simple why so much torque is yielded from nitrous use. torque is a product of hp and rpm. see below:
TQ = (hp x 5252)/rpm
so, let's say your hp peaks 500rwhp at 3800 rpm's (shortly after you turn it on), then:
500 x 5252 = 2626000/3800 = 691rwtq
if you bring on the same 500 hp at, say, 3000 rpms instead of 3800rpm, the tq soars to 875rwtq!!!! there is a challange to trying to bring on so much hp so early, such as: sufficient fuel delivery, detonation, high cylinder pressures all caused by the bigger load 3000rpm provides vs. a motor already spinning 4000rpm or more.
<small>[ August 06, 2002, 09:04 AM: Message edited by: nitrousc5 ]</small>
TQ = (hp x 5252)/rpm
so, let's say your hp peaks 500rwhp at 3800 rpm's (shortly after you turn it on), then:
500 x 5252 = 2626000/3800 = 691rwtq
if you bring on the same 500 hp at, say, 3000 rpms instead of 3800rpm, the tq soars to 875rwtq!!!! there is a challange to trying to bring on so much hp so early, such as: sufficient fuel delivery, detonation, high cylinder pressures all caused by the bigger load 3000rpm provides vs. a motor already spinning 4000rpm or more.
<small>[ August 06, 2002, 09:04 AM: Message edited by: nitrousc5 ]</small>
Re: why so much torque w/nitrous, you ask?! Yep, simple math with fractions, you make the denominator's vaule decrease then your whole value increases and vice versa (all assuming you hold the numerator constant
)
) 
Re: why so much torque w/nitrous, you ask?! The equation is correct but its not really WHY you have more TQ down low. The main reason is due to a fixed rate of nitrous flow VS a varying RPM or intake flow. More nitrous being stacked in each cylinder at lower RPMs. A two stage helps that some.
