Jetting question...
I did some math and came up with the same general conclusion that, for example, if you take a single .062 jet it equates to roughly two .043 jets. Is the quasi-reverse true? Can I use the .062 jet before a T to simulate two .043 jets? Below is a picture to explain wtf I'm talking about.

So... will the flow at each red arrow be equal to that of a .043 jet?
I would use two compression fittings and two .043 jets, and discard the .062 jet, but I'm working in an extremely narrow area, and it the assembly would become too wide. The only alternative would be a T built to hold two jets (where the red arrows are) with a 1/8 NPT male base, but it seems no one makes such a thing.
Thanks for your help!

So... will the flow at each red arrow be equal to that of a .043 jet?
I would use two compression fittings and two .043 jets, and discard the .062 jet, but I'm working in an extremely narrow area, and it the assembly would become too wide. The only alternative would be a T built to hold two jets (where the red arrows are) with a 1/8 NPT male base, but it seems no one makes such a thing.
Thanks for your help!
I would agree going this route. Why take the chance of not having the correct dispersement of the juice through the single jet, when you could have the 2 .043's getting fed from the main line.
My goal is to get equal fluid flow on both sides of the T-fitting. The base of the T is 1/8" NPT, and the two lines connecting to the T are -4AN, but the flow of both -4ANs are too much, so I need to reduce it somehow. The obvious solution was with two jets, but I couldn't find a ? x ? x 1/8" NPT T-fitting, where "?" is the socket that holds the jet, thus the reason for trying to use one jet. I did some searching around on your site, Ray, and found NX's 16096... might that be what I'm looking for?



