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need help...math question

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Old Nov 6, 2007 | 10:54 PM
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need help on this math question plz

http://i190.photobucket.com/albums/z.../mathquest.jpg
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Old Nov 6, 2007 | 11:09 PM
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all of the above.
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Old Nov 6, 2007 | 11:10 PM
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lol no such thing, come on guys I know there are mathematicians out there and this is a timed quiz for class and this problem is giving me problems. only 32 min left on quiz plz help!!!
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Old Nov 6, 2007 | 11:28 PM
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i'd just guess.
we'll all just post up our best guess... C.
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Old Nov 6, 2007 | 11:29 PM
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Number four.
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Old Nov 6, 2007 | 11:30 PM
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you could always ask jeeves?
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Old Nov 6, 2007 | 11:33 PM
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It's either the fourth one, or none of the above, been a while since I dealt with "i" (imaginary numbers if I remember right). Now you have a 50 50 shot at a guess, and I really think its none of the above.
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Old Nov 6, 2007 | 11:36 PM
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Originally Posted by Tex7387
It's either the fourth one, or none of the above, been a while since I dealt with "i" (imaginary numbers if I remember right). Now you have a 50 50 shot at a guess, and I really think its none of the above.
The only one that has 3 as a root is number four. You can use synthetic division to factor out the x - 3 root to get the polynomial down to a quadratic. Finding the other two roots is accomplished by plugging in the coefficients into the quadratic formula.
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Old Nov 6, 2007 | 11:36 PM
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Do what Donohue said... Just guess. That's exactly what I would do in geometry back in high school and it turned out good. Just picked whichever one looked right lol.
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Old Nov 6, 2007 | 11:38 PM
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Originally Posted by Shackleford
The only one that has 3 as a root is number four. You can use synthetic division to factor out the x - 3 root to get the polynomial down to a quadratic. Finding the other two roots is accomplished by plugging in the coefficients into the quadratic formula.
I knew 3 would work, but its been a while since I fooled around with synthetic division (although its coming back to me now). The others were easily eliminated by just plugging 3 in. You see this is why I said screw engineering and complex math and became an accounting major.
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Old Nov 6, 2007 | 11:41 PM
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Originally Posted by Tex7387
I knew 3 would work, but its been a while since I fooled around with synthetic division (although its coming back to me now). The others were easily eliminated by just plugging 3 in. You see this is why I said screw engineering and complex math and became an accounting major.
Haha. That's cool. But I believe most Accounting majors have to take up to Cal II. I'm a physics major, so I have quite a bit of Calculus and a little beyond to take!
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Old Nov 6, 2007 | 11:45 PM
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Originally Posted by Shackleford
Haha. That's cool. But I believe most Accounting majors have to take up to Cal II. I'm a physics major, so I have quite a bit of Calculus and a little beyond to take!
Not to my knowledge, and even so, I have taken and passed through Calc 2(I was an engineering major for a short time), and I found that Calc 3 is a bitch to pass when you don't go to class.

All those calc classes have equated to my finite math classes required for accounting so far.
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Old Nov 7, 2007 | 08:14 AM
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thanks guys it was d i got a 100 btw thanks
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Old Nov 7, 2007 | 01:28 PM
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Havent you heard of Yahoo Answers...lol j/k
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