The formula for figuring valve events. ..would that be helpful
#1
The formula for figuring valve events. ..would that be helpful
to anyone on the board. As long as you have duration and centerline you can calculate opening and closing of the valves. I was asked for this on another board after the fella called several cam companies and no one new how?
Chris
Chris
#4
6600 rpm clutch dump of death Administrator
Chris knows how, trust me on that. I think his point was that he can provide it for anyone who needs it. I put it in my Excel spreadsheet so you can plug an go. The actual formulas are in the cam thread.
https://ls1tech.com/forums/showthrea...aft+discussion
The spreadsheet is here.
http://users3.ev1.net/~black_ops/cam...calculator.xls
https://ls1tech.com/forums/showthrea...aft+discussion
The spreadsheet is here.
http://users3.ev1.net/~black_ops/cam...calculator.xls
#7
6600 rpm clutch dump of death Administrator
Originally Posted by 99 Black Bird T/A
Chris, I would be greatful for the formula.
thanks
wade
thanks
wade
From page 1 of the thread...
How to calculate VE's given duration, LSA, & ICL:
Example cam 230/236 112LSA 108ICL
IVO = ((intake duration/2)-ICL)
Ex: ((230/2)-108)= 7 BTDC (negatives indicate ATDC)
IVC = ((-IVO) + intake duration - 180)
Ex: ((-7) + 230 - 180) = 43 ABDC
ECL = ((2 * LSA) - ICL)
Ex: ((2 * 112) - 108) = 116
EVC = ((exhaust duration / 2)- ECL)
Ex: ((236 / 2) - 116) = 2 ATDC (negative indicates BTDC)
EVO = ((-EVC) + exhaust duration - 180)
Ex: ((-2) +236 - 180) = 54 BBDC
Overlap = ((intake duration + exhaust duration)/2) - (2 * LSA)
Ex: ((230+236)/2) - (2 * 112) = 9
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#12
wrencher
iTrader: (2)
Originally Posted by Revelation222
Quick question..how do you establish the ICL? It is different than the LSA? J-rod, someone... help
www.compcams.com/Technical/TimingTutorial/
#13
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Originally Posted by wrencher
This might help;
www.compcams.com/Technical/TimingTutorial/
www.compcams.com/Technical/TimingTutorial/
#14
6600 rpm clutch dump of death Administrator
Originally Posted by Revelation222
Well that gave me a headache. lol thanks. So, if you have a cam with a lsa of 114 with no advance ground in, the ICL will also be 114? But if it were ground with 4 degrees of advance the ICL would be 110? Is this correct? Assuming I got all that...you can also change the ICL by installing the cam advanced or retarded...for instance with the 114LSA ground straight up but then installed 4 degrees advanced would give us our 110ICL? Hope I got it this time.
ICL = LSA-(Advance)
So, if you have a 114LSA +0, you get a 114ICL 114-(0)=114
Most cams coming from the big name shops grind 4 degrees of advance into the cam, so you get 114-(+4)=110ICL
If the cam was retarded 4 degrees 114 -4, 114-(-4)= 118ICL.
ICL can be modified either from the manufacturer in how the cam is ground, or the end user can modify it by advancing or retarding the cam.
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Originally Posted by J-Rod
ICL = LSA-(Advance)
So, if you have a 114LSA +0, you get a 114ICL 114-(0)=114
Most cams coming from the big name shops grind 4 degrees of advance into the cam, so you get 114-(+4)=110ICL
If the cam was retarded 4 degrees 114 -4, 114-(-4)= 118ICL.
ICL can be modified either from the manufacturer in how the cam is ground, or the end user can modify it by advancing or retarding the cam.
So, if you have a 114LSA +0, you get a 114ICL 114-(0)=114
Most cams coming from the big name shops grind 4 degrees of advance into the cam, so you get 114-(+4)=110ICL
If the cam was retarded 4 degrees 114 -4, 114-(-4)= 118ICL.
ICL can be modified either from the manufacturer in how the cam is ground, or the end user can modify it by advancing or retarding the cam.