equation for displacement?
6 & 8 Second Club
Joined: Aug 2006
Posts: 2,284
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From: Illinois, RT 66 dragway area
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this is the exact formula, alot of places claim a size close, I've seen 582's listed as 585 and 698's listed at 700 for whatever reason. Go by this formula, don't go by what they list. I did the last step for him and said it was for 8 cylinders only.
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this is the exact formula, alot of places claim a size close, I've seen 582's listed as 585 and 698's listed at 700 for whatever reason. Go by this formula, don't go by what they list. I did the last step for him and said it was for 8 cylinders only.
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Your numbers will be slightly off if you don't use pi (you know, that whole 3.1415 number that is used when calculating the area of a circle). The numbers you are seeing are rounded off estimations of that (pi/4 = .7854-ish, (pi/4)*8 = 6.283-ish).
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The volume of a cylinder just equals the area of the base * height = ¶r²h
¶ = pi = 3.14159265
so: 3.14159 x (Bore/2)² x stroke = displacement of one cylinder in in³ if you enter bore and stroke in inches.
multiply this number by however many cylinders you have.
then take that number and multiply it by 0.0164 to get liters of displacement if you want to know that.
¶ = pi = 3.14159265
so: 3.14159 x (Bore/2)² x stroke = displacement of one cylinder in in³ if you enter bore and stroke in inches.
multiply this number by however many cylinders you have.
then take that number and multiply it by 0.0164 to get liters of displacement if you want to know that.
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Originally Posted by MeentSS02
I'm thinking the other guys just don't like geometry...
Calculating displacement (whether using imperial/English/fractional or metric units) is the same: surface area (Pi times the radius squared) times height times the number of cylinders. The units of the answer will change depending upon the units of measure used.
Steve
Originally Posted by Steve Bryant
You're right, at least some of the guys don't like geometry. However, this forum is for advanced performance topics.
Well, I'm a 1949 model myself which makes me 57 (58 in April). All I'm saying is that Bo Duke 01 who started this thread asked about the equation for displacement and since this is the advance performance tech forum, I would think that we would strive to help Bo or anyone understand the answer to his question. I've asked a lot of questions here and other places here on LS1Tech because I didn't know the answer and wanted to learn.
Steve
Steve
Pi r^2 (aka ¶r².... aka pie arrr squared) -- is the area of a circle. (r being the radius, and Pi being the Pi constant -- 3.14159...)
if we take that area and multiply it by a height, then we have the area of a cylinder
if we take that area of one cylinder, and multiply it by however many cylinders we have, then we have the total area... also known as displacement.
this is how i remember, and think of it... i was in elementary school when they taught me pie arr squared... so its easy to remember from there.
if we take that area and multiply it by a height, then we have the area of a cylinder
if we take that area of one cylinder, and multiply it by however many cylinders we have, then we have the total area... also known as displacement.
this is how i remember, and think of it... i was in elementary school when they taught me pie arr squared... so its easy to remember from there.
Originally Posted by andereck
Only LS1Tech Advanced Tech could complicate it beyond this.
I've participated in many of the other forums here at LS1Tech.com and in Performance-trucks.net over the last several years. Each has its own special emphasis and ground rules. Some of the discussions of cam dynamics, cylinder head aerodynamics, and other topics that are discussed here don't really belong anywhere else. However, many of these discussions have been pretty technical and advanced in nature and provide great opportunities for learning and exchanging ideas.
What thoughts do you folks who participate in this forum think about my line of reasoning?
All my best,
Steve
Originally Posted by Steve Bryant
I don't want to be rude or discourteous. However, It might be good to review the sticky for posting in this forum as opposed to some of the others https://ls1tech.com/forums/showthread.php?t=396223.
I've participated in many of the other forums here at LS1Tech.com and in Performance-trucks.net over the last several years. Each has its own special emphasis and ground rules. Some of the discussions of cam dynamics, cylinder head aerodynamics, and other topics that are discussed here don't really belong anywhere else. However, many of these discussions have been pretty technical and advanced in nature and provide great opportunities for learning and exchanging ideas.
What thoughts do you folks who participate in this forum think about my line of reasoning?
All my best,
Steve
I've participated in many of the other forums here at LS1Tech.com and in Performance-trucks.net over the last several years. Each has its own special emphasis and ground rules. Some of the discussions of cam dynamics, cylinder head aerodynamics, and other topics that are discussed here don't really belong anywhere else. However, many of these discussions have been pretty technical and advanced in nature and provide great opportunities for learning and exchanging ideas.
What thoughts do you folks who participate in this forum think about my line of reasoning?
All my best,
Steve