View Poll Results: Dual Cutouts: Before or after the X?
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Dual Cutouts-before or after X?
No kidding...TQ*RPM / 5252 is the equation a dyno will use to find the HP at the same RPM inputted for the TQ figure...and it makes a graph of it. What you just claimed I don't think is possible...
Originally Posted by dragonfly
Ferocity tell me you are kidding?? 
RWTQ * rpm / 5252 = RWHP
If you gained 50 RWTQ at 5500RPM, then you gained 53 RWHP at 5500 RPM
I would ask for your money back on that dyno run????????
RWTQ * rpm / 5252 = RWHP
If you gained 50 RWTQ at 5500RPM, then you gained 53 RWHP at 5500 RPM
I would ask for your money back on that dyno run????????
Teching In
Joined: Oct 2005
Posts: 3
Likes: 0
So you don't have a graph?
"I only gained about 2rwhp across the graph from 2500 to 6500rpm"
Lets think of it in reverse...
If you only gained 2RWHP across the graph, then at 2600RPM you should have gained 4RWTQ (That isn't 50???)
At 1300RPM you should have gained 8RWTQ (That isn't 50?????)
So What I am seeing is you are throwing info out there that is untrue, and ......frustrating, because people look for data here.
Quote:
Originally Posted by dragonfly
Ferocity tell me you are kidding??
RWTQ * rpm / 5252 = RWHP
If you gained 50 RWTQ at 5500RPM, then you gained 53 RWHP at 5500 RPM
I would ask for your money back on that dyno run????????
First of all, I said an AVERAGE gain between 2500 and 5500rpm. 5500 is not where the torque peaked at all. 5500 was a guess of where the HP peaked. I imagine the peak of the torque and hp changed from when the cutouts were open and closed. If I had a grapgh I would post it.
Today 02:34 PM
"I only gained about 2rwhp across the graph from 2500 to 6500rpm"
Lets think of it in reverse...
If you only gained 2RWHP across the graph, then at 2600RPM you should have gained 4RWTQ (That isn't 50???)At 1300RPM you should have gained 8RWTQ (That isn't 50?????)
So What I am seeing is you are throwing info out there that is untrue, and ......frustrating, because people look for data here.
Quote:
Originally Posted by dragonfly
Ferocity tell me you are kidding??
RWTQ * rpm / 5252 = RWHP
If you gained 50 RWTQ at 5500RPM, then you gained 53 RWHP at 5500 RPM
I would ask for your money back on that dyno run????????
First of all, I said an AVERAGE gain between 2500 and 5500rpm. 5500 is not where the torque peaked at all. 5500 was a guess of where the HP peaked. I imagine the peak of the torque and hp changed from when the cutouts were open and closed. If I had a grapgh I would post it.
Today 02:34 PM
