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CFM Question??

Old Aug 31, 2008 | 12:13 AM
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Does anyone know how many CFM"s a mostly stock LS1 will flow through the intake at WOT?? I'm building a true ram air setup, and was just kind of curious. Any help would be greatly appreciated.
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Old Aug 31, 2008 | 01:26 AM
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Bump for ya man!!
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Old Aug 31, 2008 | 09:44 AM
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i can log some runs today and find out for you...i just have autotap but i think there is a mass flow rate option...i am curious too to make some calculations on something else...
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Old Aug 31, 2008 | 10:47 AM
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With your LS6 intake it's in the 245 CFM range. However, you also have 1.8 rockers which will boost the flow a bit due to greater valve lift. So, I'd estimate 260 CFM.
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Old Aug 31, 2008 | 06:16 PM
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Originally Posted by LS1-450
With your LS6 intake it's in the 245 CFM range. However, you also have 1.8 rockers which will boost the flow a bit due to greater valve lift. So, I'd estimate 260 CFM.
Thats good news!! With my ram air scoop size of 2"1/2 inch / 13 inch. I figured at 60 mph I should have an intake charge of 745 cfm. If the engine exceeds that amount then the ram air effect is nullified. If at WOT i am only flowing 260 than I will have the ram air effect at a lower speed and I don't have to worry about the intake demand exceeding the ram air effect. How did you get those numbers??
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Old Aug 31, 2008 | 07:58 PM
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Go to the stickies, "intake & exhaust." An LS6 flows 245 @ .550" lift, then your rockers bring it up to .582" valve lift & the LS6 flows 260 @ .600" lift. I was a bit high @ 260, it's more like 255. In either case, your between 245-260. BTW, to get 300 CFM a big cam, & a very high flowing intake is required. Most intakes won't reach 300 CFM. So, you can be sure that the 245-260CFM is pretty close for your set-up.

BTW, there was a member in the advanced tech area of this site that did a ram air test with intake pressure measurements. You may be interested in his findings.
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Old Aug 31, 2008 | 08:51 PM
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Originally Posted by LS1-450
Go to the stickies, "intake & exhaust." An LS6 flows 245 @ .550" lift, then your rockers bring it up to .582" valve lift & the LS6 flows 260 @ .600" lift. I was a bit high @ 260, it's more like 255. In either case, your between 245-260. BTW, to get 300 CFM a big cam, & a very high flowing intake is required. Most intakes won't reach 300 CFM. So, you can be sure that the 245-260CFM is pretty close for your set-up.

BTW, there was a member in the advanced tech area of this site that did a ram air test with intake pressure measurements. You may be interested in his findings.
yeah that was me i think...ram air is a great mod i did run some autotap runs for you and the most mass air flow i saw with my cam only was 330grams/sec or 43.65lb/min...you can use which ever...hope this helps you some later man
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Old Aug 31, 2008 | 09:36 PM
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Originally Posted by chrs1313
yeah that was me i think...ram air is a great mod i did run some autotap runs for you and the most mass air flow i saw with my cam only was 330grams/sec or 43.65lb/min...you can use which ever...hope this helps you some later man
330 g/s is just about 245 CFM if I use my set-up as a reference. Seems about right for a cam only.


EDIT: Monday

chrs1313 & I have been discussing this further through PM's. Chris has pointed out that a straight conversion of 330 g/s indicates a higher CFM rate. Chris is correct. My estimate was based on a single intake runner flow @ a time using the known single rinner flow rates of my set-up, as a reference. So, for a single runner, my estimate remains valid. However, a straight mathematical conversion of 330 g/s into CFM indicates that more than one runner is filling with air @ a time. This is the case & should have been included in my estimate. To end the long story, the CFM if chris's set-up is in the neighborhood of 542 to 591 CFM.

Here is a reference calculation for you guys to check for accuracy.

2,8316.8 cm^3 / ft^3
.00129 grams / cm^3

2,8316 x .00129 = 36.53 grams / ft^3

330 grams / sec x 60 sec / min = 19,800 grams / min (measured by MAF)

19,800 / 36.53 = 542 CFM (measured by MAF) , more than one runner pulling air @ a time.


Please, all feel free to check calculations & comment, as the goal is to be accurate. Thank-you

Last edited by LS1-450; Sep 1, 2008 at 11:17 AM.
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Old Sep 1, 2008 | 12:46 PM
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Bump for Edited update
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Old Sep 1, 2008 | 05:31 PM
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Originally Posted by LS1-450
EDIT: Monday

chrs1313 & I have been discussing this further through PM's. Chris has pointed out that a straight conversion of 330 g/s indicates a higher CFM rate. Chris is correct. My estimate was based on a single intake runner flow @ a time using the known single rinner flow rates of my set-up, as a reference. So, for a single runner, my estimate remains valid. However, a straight mathematical conversion of 330 g/s into CFM indicates that more than one runner is filling with air @ a time. This is the case & should have been included in my estimate. To end the long story, the CFM if chris's set-up is in the neighborhood of 542 to 591 CFM.

Here is a reference calculation for you guys to check for accuracy.

2,8316.8 cm^3 / ft^3
.00129 grams / cm^3

2,8316 x .00129 = 36.53 grams / ft^3

330 grams / sec x 60 sec / min = 19,800 grams / min (measured by MAF)

19,800 / 36.53 = 542 CFM (measured by MAF) , more than one runner pulling air @ a time.


Please, all feel free to check calculations & comment, as the goal is to be accurate. Thank-you
WOW dude!! Yeah I'm impressed. This is one example of why LS1tech is the best car forum site on the web. People like you guys make this site what it is. Thanks for all the great info!!
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Old Sep 1, 2008 | 09:15 PM
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Originally Posted by LS1-450
Bump for Edited update
thanks for helping me out...forgot about that too and thought i was losing my mind...thought i had been out of school too long lol
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Old Sep 5, 2008 | 04:31 PM
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going to run some pressure drop test at work on monday of a K&N versus a paper filter....wanna make some guesses on the results...
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Old Sep 7, 2008 | 11:51 AM
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Originally Posted by chrs1313
going to run some pressure drop test at work on monday of a K&N versus a paper filter....wanna make some guesses on the results...

A paper filter w/ the same surface area of a K&N filter will flow better (less pressure drop). A cloth type filter (K&N) becomes an advantage when the surface area is greater than the paper filter it replaces. This is why a large cone will outflow a stock paper filter.
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Old May 19, 2010 | 06:10 PM
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Originally Posted by LS1-450
EDIT: Monday

chrs1313 & I have been discussing this further through PM's. Chris has pointed out that a straight conversion of 330 g/s indicates a higher CFM rate. Chris is correct. My estimate was based on a single intake runner flow @ a time using the known single rinner flow rates of my set-up, as a reference. So, for a single runner, my estimate remains valid. However, a straight mathematical conversion of 330 g/s into CFM indicates that more than one runner is filling with air @ a time. This is the case & should have been included in my estimate. To end the long story, the CFM if chris's set-up is in the neighborhood of 542 to 591 CFM.

Here is a reference calculation for you guys to check for accuracy.

2,8316.8 cm^3 / ft^3
.00129 grams / cm^3

2,8316 x .00129 = 36.53 grams / ft^3

330 grams / sec x 60 sec / min = 19,800 grams / min (measured by MAF)

19,800 / 36.53 = 542 CFM (measured by MAF) , more than one runner pulling air @ a time.


Please, all feel free to check calculations & comment, as the goal is to be accurate. Thank-you
How would temperature/pressure work into this formula?
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Old May 20, 2010 | 01:04 PM
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Originally Posted by Tiron
How would temperature/pressure work into this formula?
would affect air charge density
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Old May 20, 2010 | 01:32 PM
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Originally Posted by Tiron
How would temperature/pressure work into this formula?
The density of air would change, so g/cm^3 would be more or less depending upon atmospheric conditions.

FWIW doing a very basic back of the napkin calculation on an LS1's CFM flow at WOT:
346CI = 0.2 ft^3

Half of the displacement in a 4 cycle engine is covered in one crank rotation (360 degrees), or 0.1 ft^3.

0.1 ft^3 per RPM X 6,000 rpms (near redline) = 600 CFM of theoretical air consumption.
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Old May 20, 2010 | 03:28 PM
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Originally Posted by NHRATA01
The density of air would change, so g/cm^3 would be more or less depending upon atmospheric conditions.
Yes, but how would I calculate how much it will change? If I'm converting g/s to cf/m the density would make a difference.
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Old May 21, 2010 | 12:05 PM
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Originally Posted by Tiron
Yes, but how would I calculate how much it will change? If I'm converting g/s to cf/m the density would make a difference.
You could calculate the density using a form of the ideal gas law:

density = pressure / (R * T)

Where pressure is absolute pressure (ie air pressure at sea level = 14.7 psi)

R is a constant and T is the absolute temperature (in Kelvin or Rankine).

Or to do it the easy way, just use this link and convert to your chosen units: http://www.denysschen.com/catalogue/density.asp
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Old May 21, 2010 | 02:04 PM
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Thanks, that's what I was looking for.

I'm writing a script for ScanXL from Palmer Performance to calculate the current volumetric efficiency. So using an online converter won't help too much. I have it working, but I want to make it more accurate by including density calculations.
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