HP tuners VCM controlled shift light
#1
HP tuners VCM controlled shift light
Ok guys I have a tech question for you. I found a write up on a VCM controlled shift light and it said to wire a couple of LED's in line from a fused 12v source and to the red c2 connector pin # 47. Now everything is pretty straight forward and easy eccept for the part where I don't have pin# 47 wire, a spot for one but no wire. What I'm trying to firgure out here is, which pin on a 2002 will work like pin #47 on the 98 that will ground at specified rpm. Any help would be greatly appreciated. Well as I look over this more he said he got the pin #47 to activate at disered rpm. Is putting in a wire and female receptacle for the pin a consideration? I would think this is what he is getting at. If anyone wants this info it's on the HP tuners forum under VCM controlled shift light. Thanks
Last edited by STREETSLEEPER; 07-22-2010 at 04:57 PM.
#3
You don't have a pin/wire at #47 because you have an m6. On an auto, pin #47 controls the 2-3 shift solenoid. That's why this will only work on an m6 or a non electronically controlled trans.
Just follow the write up, install a pin and run a wire to your shift light. The PCM will ground the circuit to activate the light. Pin #79 controls the IAC, so that won't work either.
Just follow the write up, install a pin and run a wire to your shift light. The PCM will ground the circuit to activate the light. Pin #79 controls the IAC, so that won't work either.
#4
Thanx
You don't have a pin/wire at #47 because you have an m6. On an auto, pin #47 controls the 2-3 shift solenoid. That's why this will only work on an m6 or a non electronically controlled trans.
Just follow the write up, install a pin and run a wire to your shift light. The PCM will ground the circuit to activate the light. Pin #79 controls the IAC, so that won't work either.
Just follow the write up, install a pin and run a wire to your shift light. The PCM will ground the circuit to activate the light. Pin #79 controls the IAC, so that won't work either.