383 H/C/I Results!!
01-23-2018, 06:01 PM
#685
7 Second Club
01-23-2018, 06:37 PM
#686
11 Second Club
Thread Starter
Sup man.
Nice. From the 330' back the difference, from my cars slip, is hundos at each timing point. Weather that slip is real or not lol. You can def tell the car in other lane is faster. Maybe some peeps get hooked on the 123mph. Lol.
Nice. From the 330' back the difference, from my cars slip, is hundos at each timing point. Weather that slip is real or not lol. You can def tell the car in other lane is faster. Maybe some peeps get hooked on the 123mph. Lol.
01-23-2018, 07:09 PM
#688
7 Second Club
I've run 1.852 in the 1/4.
I don't have vid, but the guy beside me said it was legit and I have a slip for even more proof!
01-23-2018, 07:31 PM
#690
7 Second Club
01-24-2018, 08:41 AM
#691
10 Second Club
iTrader: (8)
There are some things out of the realm of possibilities and there are some things that's not.
I wouldn't be proud of that at all in your shoes
The pass was normal till for him....on the front 1/2. They were on him for running 9s with no cage so he was letting out somewhere in the back half.
I find it funny you guys claim to read slips so well and tell bogus **** but some how keep overlooking this.
I find it funny you guys claim to read slips so well and tell bogus **** but some how keep overlooking this.
01-24-2018, 08:50 AM
#693
01-24-2018, 08:59 AM
#694
We don't have to make up anything, you've done enough of that for all of us in here. Even the "crew" is silent in here cause deep down everyone knows its crap, you just can't bring yourself to own up to it. Just can't bring yourself to consider ANY other possibility like he pedaled it or anything. Its sad really.
01-24-2018, 09:28 AM
#695
Ok the other car was obviously much faster. He treed you by 0.162 sec, yet you caught up and were ahead by 0.025 sec at the 60'. Than he ran away and smoked ya by 330' and it continued to get worse from there until he let off somewhere in the back-half. Truly amazing.
What tire were you on during this run? Just curious.
What tire were you on during this run? Just curious.
Last edited by R6cowboy; 01-24-2018 at 10:40 AM.
01-24-2018, 09:42 AM
#696
7 Second Club
We don't have to make up anything, you've done enough of that for all of us in here. Even the "crew" is silent in here cause deep down everyone knows its crap, you just can't bring yourself to own up to it. Just can't bring yourself to consider ANY other possibility like he pedaled it or anything. Its sad really.
They must have been going 400 mph!
01-24-2018, 12:41 PM
#699
Moderator
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Join Date: Jul 2014
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I had to convert all this to metric to figure it out, so bear with me on this, and please be patient with the equations etc...
distance=1/2 x acceleration x time squared. so, acceleration = 2 x d / t^2 = 25.4 m/s/s or 2.6G. Now before everyone flips out over that, top fuel sees >5G at launch. Effective coefficient of friction of racing tires seems to range from 1.8 to 4 before you get into top fuel stuff. So, 2.6G checks out.
Next, velocity = acceleration x time = 25.6 * 1.2 = 30.5 m/s = 68 MPH. So, he would have had to be in second gear by the end of his 60'. At this point though, the engine power and wind resistance would really become limiting, so acceleration would fall off greatly in third gear and especially 4th.
next F=ma. Using 3250 as RW, that's 1477 Kg x 25.4 m/s/s = 37.4KN of force, or 8429 lbf.
I used 350 lbs of torque for this, but 350 x gearing and correcting for tire size gets it to 8928.3 lbF available at the pavement.
So, if the car is set up perfectly, and everything goes right, and the driver executes flawlessly, it's technically possible by the math.
Edit, using 1.26 and not 1.2, drops to 2.3G, 65mph at the 60' mark, and 7650lbf to push the car. The hard part is average power vs instantaneous power, etc, so you don't get the force constantly like a classroom physics world
distance=1/2 x acceleration x time squared. so, acceleration = 2 x d / t^2 = 25.4 m/s/s or 2.6G. Now before everyone flips out over that, top fuel sees >5G at launch. Effective coefficient of friction of racing tires seems to range from 1.8 to 4 before you get into top fuel stuff. So, 2.6G checks out.
Next, velocity = acceleration x time = 25.6 * 1.2 = 30.5 m/s = 68 MPH. So, he would have had to be in second gear by the end of his 60'. At this point though, the engine power and wind resistance would really become limiting, so acceleration would fall off greatly in third gear and especially 4th.
next F=ma. Using 3250 as RW, that's 1477 Kg x 25.4 m/s/s = 37.4KN of force, or 8429 lbf.
I used 350 lbs of torque for this, but 350 x gearing and correcting for tire size gets it to 8928.3 lbF available at the pavement.
So, if the car is set up perfectly, and everything goes right, and the driver executes flawlessly, it's technically possible by the math.
Edit, using 1.26 and not 1.2, drops to 2.3G, 65mph at the 60' mark, and 7650lbf to push the car. The hard part is average power vs instantaneous power, etc, so you don't get the force constantly like a classroom physics world
Last edited by Darth_V8r; 01-24-2018 at 12:53 PM.
01-24-2018, 01:01 PM
#700
10 Second Club
iTrader: (8)
We don't have to make up anything, you've done enough of that for all of us in here. Even the "crew" is silent in here cause deep down everyone knows its crap, you just can't bring yourself to own up to it. Just can't bring yourself to consider ANY other possibility like he pedaled it or anything. Its sad really.
Now you guys on the other hand have tried to make up everything to discredit it.......even using physicals
Ok the other car was obviously much faster. He treed you by 0.162 sec, yet you caught up and were ahead by 0.025 sec at the 60'. Than he ran away and smoked ya by 330' and it continued to get worse from there until he let off somewhere in the back-half. Truly amazing.
What tire were you on during this run? Just curious.
What tire were you on during this run? Just curious.
He had a much more powerful car. But that don't always correlate to 60' performance.
I had to convert all this to metric to figure it out, so bear with me on this, and please be patient with the equations etc...
distance=1/2 x acceleration x time squared. so, acceleration = 2 x d / t^2 = 25.4 m/s/s or 2.6G. Now before everyone flips out over that, top fuel sees >5G at launch. Effective coefficient of friction of racing tires seems to range from 1.8 to 4 before you get into top fuel stuff. So, 2.6G checks out.
Next, velocity = acceleration x time = 25.6 * 1.2 = 30.5 m/s = 68 MPH. So, he would have had to be in second gear by the end of his 60'. At this point though, the engine power and wind resistance would really become limiting, so acceleration would fall off greatly in third gear and especially 4th.
next F=ma. Using 3250 as RW, that's 1477 Kg x 25.4 m/s/s = 37.4KN of force, or 8429 lbf.
I used 350 lbs of torque for this, but 350 x gearing and correcting for tire size gets it to 8928.3 lbF available at the pavement.
So, if the car is set up perfectly, and everything goes right, and the driver executes flawlessly, it's technically possible by the math.
Edit, using 1.26 and not 1.2, drops to 2.3G, 65mph at the 60' mark, and 7650lbf to push the car.
distance=1/2 x acceleration x time squared. so, acceleration = 2 x d / t^2 = 25.4 m/s/s or 2.6G. Now before everyone flips out over that, top fuel sees >5G at launch. Effective coefficient of friction of racing tires seems to range from 1.8 to 4 before you get into top fuel stuff. So, 2.6G checks out.
Next, velocity = acceleration x time = 25.6 * 1.2 = 30.5 m/s = 68 MPH. So, he would have had to be in second gear by the end of his 60'. At this point though, the engine power and wind resistance would really become limiting, so acceleration would fall off greatly in third gear and especially 4th.
next F=ma. Using 3250 as RW, that's 1477 Kg x 25.4 m/s/s = 37.4KN of force, or 8429 lbf.
I used 350 lbs of torque for this, but 350 x gearing and correcting for tire size gets it to 8928.3 lbF available at the pavement.
So, if the car is set up perfectly, and everything goes right, and the driver executes flawlessly, it's technically possible by the math.
Edit, using 1.26 and not 1.2, drops to 2.3G, 65mph at the 60' mark, and 7650lbf to push the car.
There has been less powerful cars 60' in 1.2 range and never leave the 11s. They are typically a superstock type car.