LS1 goes DOWN to turbo INTEGRA!
05-25-2010, 05:08 PM
#61
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05-25-2010, 05:57 PM
#64
I'm pretty sure that you're right. I think I've seen this before as well, but it proves how easily people are baited, lol.
05-25-2010, 06:07 PM
#65
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05-25-2010, 06:52 PM
#66
Well I appologize to you. I get pretty crazy in youtube comments mainly because everyone and there brother on youtube are D-bags in there vids and comments. There are "stereotypes" that go with different cars, IE mullets for 3rd gens, hispanics for hondas and integras, etc, etc. By me unfortunately a lot of the stereotypes are true and the owners/drivers act like A-holes so it magnifies the stereotype. Didn't mean to offend you at all. I have freinds of all different races and colors, and we are even racial in a funny way to each other half the time. Anyways, my point was that this integra driver is a failure and should be destroyed!
Thanks bro! Thats very cool of you... I didnt have any problems with what you said other then the "spic" part.. other then that it was all good.. By the way nice to meet you bro!
05-25-2010, 10:35 PM
#69
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Guys, I wasn't making fun of EVERYONE that owns a honda or acura, just the "stereotypical" ones that dress like thugs with the flat brimmed hats, clothes 10 times thier size, and drive laying down with the seat completely back. I have a 1990 civic as a daily and wouldn't trade that damn thing for any other beater. 34 mpg around town and it rides smooth as silk!
05-25-2010, 11:17 PM
#70
I'll trade in a few MPG's for my safety. Simple physics in a collision. The more massive vehicle wins.
(F)orce=(m)****(a)celleration
Lets say there are two cars, 1 and 2. Car 1 being more massive than Car 2.
So, if Car 1 and Car 2 are in a collision, the force exerted on each car is equal (according to Newton),
so that means F1=m1*a1 and F2=m2*a2
Since F1=F2, m1*a1=m2*a2
Since, m1>m2 this means that a1<a2
Since a1<a2, Car 1 will undergo less acceleration in the collision and therefore its occupants will be more likely to sustain a lesser degree of injury than Car 2's occupants. The greater the difference in mass of the vehicles the greater the difference in acceleration will be.
I know a complete collision is not as simple as F=ma, but this is a darn good estimation for a head on collision. To put it in perspective, it takes anywhere from 40-75+ g's of instant acceleration to kill some one.
Sorry, I am bored.
(F)orce=(m)****(a)celleration
Lets say there are two cars, 1 and 2. Car 1 being more massive than Car 2.
So, if Car 1 and Car 2 are in a collision, the force exerted on each car is equal (according to Newton),
so that means F1=m1*a1 and F2=m2*a2
Since F1=F2, m1*a1=m2*a2
Since, m1>m2 this means that a1<a2
Since a1<a2, Car 1 will undergo less acceleration in the collision and therefore its occupants will be more likely to sustain a lesser degree of injury than Car 2's occupants. The greater the difference in mass of the vehicles the greater the difference in acceleration will be.
I know a complete collision is not as simple as F=ma, but this is a darn good estimation for a head on collision. To put it in perspective, it takes anywhere from 40-75+ g's of instant acceleration to kill some one.
Sorry, I am bored.
05-26-2010, 12:59 AM
#72
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I'll trade in a few MPG's for my safety. Simple physics in a collision. The more massive vehicle wins.
(F)orce=(m)****(a)celleration
Lets say there are two cars, 1 and 2. Car 1 being more massive than Car 2.
So, if Car 1 and Car 2 are in a collision, the force exerted on each car is equal (according to Newton),
so that means F1=m1*a1 and F2=m2*a2
Since F1=F2, m1*a1=m2*a2
Since, m1>m2 this means that a1<a2
Since a1<a2, Car 1 will undergo less acceleration in the collision and therefore its occupants will be more likely to sustain a lesser degree of injury than Car 2's occupants. The greater the difference in mass of the vehicles the greater the difference in acceleration will be.
I know a complete collision is not as simple as F=ma, but this is a darn good estimation for a head on collision. To put it in perspective, it takes anywhere from 40-75+ g's of instant acceleration to kill some one.
Sorry, I am bored.
(F)orce=(m)****(a)celleration
Lets say there are two cars, 1 and 2. Car 1 being more massive than Car 2.
So, if Car 1 and Car 2 are in a collision, the force exerted on each car is equal (according to Newton),
so that means F1=m1*a1 and F2=m2*a2
Since F1=F2, m1*a1=m2*a2
Since, m1>m2 this means that a1<a2
Since a1<a2, Car 1 will undergo less acceleration in the collision and therefore its occupants will be more likely to sustain a lesser degree of injury than Car 2's occupants. The greater the difference in mass of the vehicles the greater the difference in acceleration will be.
I know a complete collision is not as simple as F=ma, but this is a darn good estimation for a head on collision. To put it in perspective, it takes anywhere from 40-75+ g's of instant acceleration to kill some one.
Sorry, I am bored.
05-26-2010, 08:10 AM
#75
TECH Enthusiast
I havent bother to read through the previous 4 pages of BS. So I wont pretend I have.
05-26-2010, 12:52 PM
#78
Between the questionable origin and validity of the video, the racist remarks, the 90% off-topic responses, and the overall lack of intelligence displayed in this thread, I'm pretty sure no further explanation is needed as to why I'm locking it.
My god this is a sad excuse for a SR&K thread...
My god this is a sad excuse for a SR&K thread...
