Find the exact arc length of the parametric curve without eliminating the parameter.
#22
TECH Addict
Thread Starter
iTrader: (12)
Join Date: Sep 2004
Location: Houston, Texas
Posts: 2,693
Likes: 0
Received 0 Likes
on
0 Posts
Haha. Yeah, I think the answer is Arnold Schwarzenegger.
I got someone else to help me. You had to be a little tricky under the radical: find a common denominator then use u-substitution for the numerator, square it, etc. This is Cal II, by the way. The Cal book at San Jac Central blows hardcore. I like my Cal book from South much better.
I got someone else to help me. You had to be a little tricky under the radical: find a common denominator then use u-substitution for the numerator, square it, etc. This is Cal II, by the way. The Cal book at San Jac Central blows hardcore. I like my Cal book from South much better.
#27
TECH Junkie
iTrader: (1)
Join Date: Nov 2004
Location: TX
Posts: 3,215
Likes: 0
Received 0 Likes
on
0 Posts
Originally Posted by Shackleford
Haha. Yeah, I think the answer is Arnold Schwarzenegger.
I got someone else to help me. You had to be a little tricky under the radical: find a common denominator then use u-substitution for the numerator, square it, etc. This is Cal II, by the way. The Cal book at San Jac Central blows hardcore. I like my Cal book from South much better.
I got someone else to help me. You had to be a little tricky under the radical: find a common denominator then use u-substitution for the numerator, square it, etc. This is Cal II, by the way. The Cal book at San Jac Central blows hardcore. I like my Cal book from South much better.
When your on campus using a computer, type "apps" in the url and you can use Mathematica and some other neat programs to help you out.... You probably already know this.....