Math hw help please
Math hw help please Ok im stuck on this one can any math people help me please. Thanks
http://i190.photobucket.com/albums/z...stupidmath.jpg
http://i190.photobucket.com/albums/z...stupidmath.jpg
Trending Topics
LS1 Tech Stories
The Best V8 Stories One Small Block at Time
Gas Monkey Built a 6-Wheel Ferrari Testarossa With a Corvette LT4 Engine
Verdad Gallardo
7 Most Reliable High-Performance Engines GM Has Ever Built
Verdad Gallardo
Amazing '71 Camaro Restomod Is Modern Muscle Car Under the Skin
Verdad Gallardo
6 Common C5 Corvette Failures and What's Involved In Repairing Them
Pouria Savadkouei
Retro Modern Bandit Pontiac Trans AM Comes With Burt Reynolds' Autograph
Verdad Gallardo
Top 10 Greatest Cadillac V Series Performance Models Ever, Ranked
Pouria Savadkouei
Top 10 Most Powerful Chevy Trucks Ever Made!
Hennessey's New Supercharged Silverado ZR2 Has 700 HP
Verdad Gallardo
Coachbuilt N2A Anteros Is an LS2-Powered C6 Corvette In Italian Clothes
Verdad Gallardo
This is true but don't forget that:
log9(1/x) = log9(1) -log9(x)
noting:
log9(1) = 0
therefore:
-3 = -log9(x)
or:
3 = log9(x)
Answer E.
Or a simpler method would be to say that:
9^-3 = 1/x = x^-1
so:
9^3 = x^1 = x
or:
3 = log9(x)
Answer E.
Somebody should check my sanity but I believe that is the correct answer.
This is true but don't forget that:
log9(1/x) = log9(1) -log9(x)
noting:
log9(1) = 0
therefore:
-3 = -log9(x)
or:
3 = log9(x)
Answer E.
Or a simpler method would be to say that:
9^-3 = 1/x = x^-1
so:
9^3 = x^1 = x
or:
3 = log9(x)
Answer E.
Somebody should check my sanity but I believe that is the correct answer.
log9(1/x) = log9(1) -log9(x)
noting:
log9(1) = 0
therefore:
-3 = -log9(x)
or:
3 = log9(x)
Answer E.
Or a simpler method would be to say that:
9^-3 = 1/x = x^-1
so:
9^3 = x^1 = x
or:
3 = log9(x)
Answer E.
Somebody should check my sanity but I believe that is the correct answer.
