indefinite integrals
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indefinite integrals
Evaluate ʃ x (-4x^2 - 8)^6 dx
A. -1/28 (-4x^2-8)^7 + C
B. -1/8 (-4x^2+8)^7 + C
C. 1/14 (-4x^2-8)^7 + C
D. -1/56 (-4x^2-8)^7 + C
E. 1/7 (-4x^2-8)^7 + C
can anyone help me on this problem
The answer is not B because thats what i got but if u know how to do this problem could u also show some work of how to get the answer.
Thanks
A. -1/28 (-4x^2-8)^7 + C
B. -1/8 (-4x^2+8)^7 + C
C. 1/14 (-4x^2-8)^7 + C
D. -1/56 (-4x^2-8)^7 + C
E. 1/7 (-4x^2-8)^7 + C
can anyone help me on this problem
The answer is not B because thats what i got but if u know how to do this problem could u also show some work of how to get the answer.
Thanks
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My TI-89 spit out 1.20533E20....pretty sure that's not right since there's not an upper or lower bound to evaluate it lol, stupid calculator. Can't do it on paper it's just been too long lol...
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LOL don't sweat it. I've got a BS in physics, M Engr in mechanical and was working on a phd studying turbomachinery. Got bored and now I'm teaching high school physics and math so I see it pretty often. Just saving for heads and cam now........
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lol anytime. I'm always on here reading, but don't post very often. Our server will let me read the site but not post for some reason. But I'm teaching in the Cy-Fair district starting in August so I think that may be pretty close and my girl is from Wharton so I know the area pretty "okay"