Drivetrain Losses
Hi Tuner@Straightline
I started a thread mid February on the HP Tuner Forum (3 pages/50 posts a lot of screenshots) regarding the Torque Histogram here:
http://www.hptuners.com/forum/showthread.php?t=10401
At the end it becomes clear that this device is useless because inaccurate.
Christian
Not really.
Maybe your dyno reads low?
This is really a useless debate that can never be answered correctly. oponions are all we have and facts are impossible.
How in the world can you make more power, and lose more power when you are accelerating the same masses with the same inertia.
Once again, refer to the search button at the top of the page and you will see Tony Mamo's gain on an engine dyno of 60 hp show up 60 hp on a chassis dyno, giving the same exact drvietrain loss.
Also, the torque calculation is not accurate. It varies with airflow, timing, ect. My moms Grand Am said 270 ft-lbs on a stock v6, and my car said 450 ft-lbs and I dyno 437 ft-lbs. You can not go by this at all. Also, this parameter is can be logged on many cars. Bottom line here is the only thing that matters is what the car puts to the ground. Anyone trying to advertise engine hp as what they make need a swift kick in the nuts. That is like saying, oh my car would run 7's if it were 1500 lbs lighter. It is what it is.
Last edited by WS6FirebirdTA00; Jun 3, 2007 at 03:25 PM.
http://www.hptuners.com/forum/showpo...0&postcount=32
And my post below will bring you directely to Tony Mamo thread about the subject:
http://www.hptuners.com/forum/showpo...5&postcount=38
Christian
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All those procedures are pretty well described with the correct measurements and for the Torque Histogram the final conclusion.
Christian
Some work has been done on HP Tuner Forum about that, remember well...
I mention in my post above the references:
Please reread the post #2 & #7.
All those procedures are pretty well described with the correct measurements and for the Torque Histogram the final conclusion.
Christian
How in the world can you make more power, and lose more power when you are accelerating the same masses with the same inertia.
Once again, refer to the search button at the top of the page and you will see Tony Mamo's gain on an engine dyno of 60 hp show up 60 hp on a chassis dyno, giving the same exact drvietrain loss.
Also, the torque calculation is not accurate. It varies with airflow, timing, ect. My moms Grand Am said 270 ft-lbs on a stock v6, and my car said 450 ft-lbs and I dyno 437 ft-lbs. You can not go by this at all. Also, this parameter is can be logged on many cars. Bottom line here is the only thing that matters is what the car puts to the ground. Anyone trying to advertise engine hp as what they make need a swift kick in the nuts. That is like saying, oh my car would run 7's if it were 1500 lbs lighter. It is what it is.
correct me if im wrong.... but the more power you make the more power things will flex and bend, thus causing further losses of HP??? at least thats the way id see it.
F=ma where force = mass x acceleration already indicates that. Since horsepower is a measure of acceleration in the end. The relationship says if acceleration goes up, so must the force required.
What it comes down to is if you intend to accelerate something faster, it will take more power to increase the acceleration. So x percentage is going to take up power from the engine to turn the mass of the drivetrain. Since you want the car to move faster, thus the drivetrain mass to spin faster, more power will be used in relation to the increase in acceleration of the car.
F=ma where force = mass x acceleration already indicates that. Since horsepower is a measure of acceleration in the end. The relationship says if acceleration goes up, so must the force required.
What it comes down to is if you intend to accelerate something faster, it will take more power to increase the acceleration. So x percentage is going to take up power from the engine to turn the mass of the drivetrain. Since you want the car to move faster, thus the drivetrain mass to spin faster, more power will be used in relation to the increase in acceleration of the car.
You are over-simplifying the equation, I will dig some more up...
Last edited by WS6FirebirdTA00; Jun 4, 2007 at 04:15 PM.
I understand where you come from on your explanation, but the bottom line is this is not what is actually seen.
I guess somebody would need to find out how much power it takes to turn the drivetrain at different RPMs.
There are way too many variations in driveline combos to affix a fixed number. The only true way to know the efficiency of your driveline is to dyno the engine first, then add the drivetrain.
Also to address the hand thing, you can "move" the whole thing by hand, but how many revolutions per minute, how about acceleration of the rpm? Once you get the mass moving, the initial hard push, afterwards all you are doing is overcoming the friction of the components within the lubricants.
To say "15%" is a generalization. A simple change of 16 to 17's can affect that for the worse due to increase or decrease weight (depends on the rim/tire combo). Even fluids will affect the efficiency.
In the end, that simplification is the best way to get the point across to many people. If you want to go faster, more power will be needed and more will be lost to the drivetrain.





