438 In A 6.0L

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Nov 24, 2005 | 09:24 AM

Z240LS1

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From: KSA Eastern Provence

438 In A 6.0L

Hi every 1

I am planning on a 438 Rotating Assembly kit to be used in a 6.0L iron block, but I am not sure if the 6.0L iron block can handle 4.125 bore or not.

- Did any of you tried it or heard about it?

Please let me know.

Chevy 438 LS1 Rotating Assembly kit - 4.100 Stroke - 6.125 Rod - 4.125" Bore.

Nov 24, 2005 | 09:28 AM

dame

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From: berkeley ca

your not going to get that size bore out of the iron block......your gonna have to shell out the money for a resleeved block if you want those cubes (or go c5-r)

Nov 24, 2005 | 10:06 AM

383ss

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search is your friend. this has been beat to death. 4.030 is standard. you can do 4.060 if you have the block thoroughly checked out.

Nov 25, 2005 | 01:12 PM

Firehawk441

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This is true. If you can go .060 with your block, you will end up with 427 cu.in.

Nov 25, 2005 | 01:30 PM

cyphur

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Quote:

Originally Posted by Firehawk441

This is true. If you can go .060 with your block, you will end up with 427 cu.in.

Even then, I wouldn't want to push that too hard on a daily driver. Maybe on a race block only......

Go with a resleeved for that kind of bore.

Nov 25, 2005 | 01:54 PM

n2o junkee

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I know this is a little off topic but does any of you guys know the formula to find how many cubes I will have.

Nov 26, 2005 | 12:45 AM

Solid346

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From: Kuwait / USA

0.7854 x 8 x bore size x bore size x stroke size

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Nov 27, 2005 | 11:34 AM

Z240LS1

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From: KSA Eastern Provence

Thanks for your replies.

Quote:

Originally Posted by cyphur_traq

Even then, I wouldn't want to push that too hard on a daily driver. Maybe on a race block only......

Go with a resleeved for that kind of bore.

cyphur_traq,
Can I use 4.125 bore sleeves in a 5.7L aluminum block?

Nov 27, 2005 | 11:51 AM

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Firehawk441

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Yes you can resleeve your block.

Dec 4, 2005 | 04:11 PM

#11

Gm-LSX

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From: Germany

Hi

Will a 4.040" overbore work w/o Sonic Check or other Tests?
Search turned out negative (To get the classical T/A 400 Cubes For Action with a short 3.9" Stroke)

(Bore/2)² x Pi x Stroke x Number of Zylinders will also work.