Ok im stuck on this one can any math people help me please. Thanks

http://i190.photobucket.com/albums/z...stupidmath.jpg

 

e=mc2

 

Thanks






FOR NOT HELPING ME

 

I think its E but can anyone second that???

 

Wow. This has been awhile. Haha.

F.

 

log functions got to love precal

 

log (base 9) of 1/x = -3

 

Its (f), none of the above.

Because y= logb(x) is equal to x=b^y

So, substitute y=-3, b=9, and (x) is (1/x)

you get -3 = log9(1/x)

at least thats what I got

 

I concur. I corroborated that previous to yours.

 

great minds think alike

 

Log base 9 (1/X) = -3

Answer choice E.

 

And someone already did it

 

psshhht, f*ck math!

 

haha u and me both

 

This is true but don't forget that:

log9(1/x) = log9(1) -log9(x)

noting:

log9(1) = 0

therefore:

-3 = -log9(x)

or:

3 = log9(x)


Answer E.



Or a simpler method would be to say that:

9^-3 = 1/x = x^-1

so:

9^3 = x^1 = x

or:

3 = log9(x)

Answer E.


Somebody should check my sanity but I believe that is the correct answer.

 

You are correct, Sir. I should have taken it a bit further with the log properties.

 

oh wow, **** this whole thread hahaha

 

Man I'm glad I forgot math. Dammit I have to take that next semester tho...

 

im taking statistics next semseter..

 

so 2+2 is what again lol