?? Dimly lit check engine light. No codes present.
When I turn the key to on the light is bright and working correctly. When I start the car the light goes out, but not completely out. The car is running great and I have no codes. I'm running an LS1 / T56 and LS1 harness.
I'm using an LED for my check engine light and it does have a resistor built into it already. It's acting like the pcm is not going completely open in normal state to turn the light off.
There is just enough residual current to dimly light the LED then when fully on it will be blindingly bright. I use LEDs for that purpose exclusively so I can ensure it is functional when a code IS set.
The residual current is not enough to illuminate a std blight bulb.
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There is just enough residual current to dimly light the LED then when fully on it will be blindingly bright. I use LEDs for that purpose exclusively so I can ensure it is functional when a code IS set.
The residual current is not enough to illuminate a std blight bulb.
OP what color is the LED you're using? (is the casing tinted or the LED that specific color?) What's the resistor value? Do you know the resistance/ Watts of the stock light bulb? Maybe you want to make sure the ECM sees the same current as it would with the stock bulb?
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Not sure if a "resistor built into it" on a 12 V LED equals adding a resistor in series.
Now for a bit of electronics theory. Most newer high intensity led drop about 3-4 volts. Subtract that from 13 volts leaves you with 10 volts to drop across the resistor. Ohms law says, 10 volts dropped across 10,000 ohms is 0.01 amps or 10ma. 10 ma through the led will illuminate it brightly. Now with less than 12 volts applied (no code set). There will be considerably less current but just enough to forward bias the led and make it glow very dim.
Sorry but is the engineering stink coming out in me. ;-)
Last edited by aknovaman; Nov 17, 2012 at 06:13 PM.
J.
Now for a bit of electronics theory. Most newer high intensity led drop about 3-4 volts. Subtract that from 13 volts leaves you with 10 volts to drop across the resistor. Ohms law says, 10 volts dropped across 10,000 ohms is 0.01 amps or 10ma. 10 ma through the led will illuminate it brightly. Now with less than 12 volts applied (no code set). There will be considerably less current but just enough to forward bias the led and make it glow very dim.
Sorry but is the engineering stink coming out in me. ;-)
Last edited by Bo185; Nov 19, 2012 at 05:24 PM.








