I have a loaded question
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Maybe its just too early for me to think about things like this, who knows.
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Torque on the other hand is a rotational force. Torque is a measure of how much a force acting on an object causes that object to rotate. Torque = radius x force. Well on a dyno the force is being measured and the radius is also known for the spinning drum, so Torque can be calculated.
I'm sorry, I'm a 4th year Mechanical Engineer at Michigan Tech and I just couldn't help but to try to apply myself here.
Torque on the other hand is a rotational force. Torque is a measure of how much a force acting on an object causes that object to rotate. Torque = radius x force. Well on a dyno the force is being measured and the radius is also known for the spinning drum, so Torque can be calculated.
I'm sorry, I'm a 4th year Mechanical Engineer at Michigan Tech and I just couldn't help but to try to apply myself here.
Couldn't have said it better myself
I love physics!
It could also be 1 lb. moved 33,000 feet in a minute, or 181.659 lbs. moved 181.659 feet in one minute, or 550 lbs. 1 foot in 1 second, 6600 lbs. 1 inch in 1 second, etc.
-4th Year Mathematics Major
Torque at the wheels is the only thing that matters in making the car go faster. At the wheels, horsepower can be disregarded. The question that statement brings up is this - If a car can get an enormous amount of torque at 3k RPMs, then why not shift early to keep the torque up? The answer - gears. If you're making lots of torque at a low RPM in 1st gear, that's good. As you increase the RPMs the torque falls off, so you're not accelerating as quickly. However, if you were to shift to 2nd to get back to your peak torque, your torque is higher yet your power is lower. In 1st gear with the higher HP, the gears can make more torque at the wheels. In 2nd gear with the higher flywheel torque, your actual torque at the wheels will be lower due to the lack of horsepower. It's better to put down a little less torque in 1st at a high RPM than to shift to 2nd and produce a lot of torque at a lower RPM.
At the wheels you want torque to move the car. That's all that matters. At the flywheel, however, you want power. Power can be converted to torque by the transmission. So, power at the flywheel is fuel for the transmission to make torque, which it sends to the wheels. And, as we all know, torque at the wheels makes wheel stands, 1/4-mile times, and ricer excuses.
I could be totally wrong, but in my head it works out ok
Don't forget its not quite 15,595 since you must factor in the diameter of the tires.
answer:
because its measuring the RPMs of the motor.. not the RPMs of the axle.
What is confusing is that in Imperial measure energy and torque have the same units. Torque is usually defined as force times distance (lb.ft) while energy is measured in (ft.lb). They are used interchangeably so people think they are the same thing.
If you have 1000 lb.ft of torque at the wheels (engine torque multiplied by gearing) and you sweep one full wheel rotation (360 degrees is 2*pi radians) you have performed 6283 ft.lb of work (you have used 6283 ft.lb of energy). If the wheel is rotating at 1000 RPM (or 16.7 rev/s) (this would be ~80 mph) then you are expending 6283 ft.lb of work with every revolution, therefore this is 16.7 rev/sec*6283 ft.lb (per revolution) = 104720 ft.lb/s Since 550 ft.lb/sec is 1 hp , this is 190 hp.
I am not implying you need 190 hp to trvel at 80 mph but if you are accelerating at that moment you can be putting 1000 ft.lb to the wheels.
Last edited by BJM; Aug 9, 2006 at 04:27 PM.

when something is in the wrong forum and needs to be moved, theres no need to post in the thread... just take the first post and report it... then one of the mods will know to move it.
posting like that in the forum doesnt do anything besides start fights.







