Ya i was about 15 years ago..I havent programmed in a long long time, other then scripting in linux and what not 
Paging Purevl
Paging RhodeIslandRed ;) Rumor has it that you are good in C++,
is this true?
If so can I ask you a few questions??
is this true?
If so can I ask you a few questions??
Last edited by lilstephsls1; Oct 19, 2005 at 10:58 PM. Reason: retarded
maybe you know this then danno, its pretty simple but i cant find an answer. I am using a function to ask the user to enter in a number that they can pick between 9 different commands to do (ie add, subtract, modus, multi..etc). So i have to ask the user to enter a number between 0 & 9 depending on what action they want. Now if they enter a 10 or anything else, I am suppose to terminate the whole program. How the hell do i make the program terminate? Do i use 'return 0;' during that function, or do i use another code?
Originally Posted by lilstephsls1
maybe you know this then danno, its pretty simple but i cant find an answer. I am using a function to ask the user to enter in a number that they can pick between 9 different commands to do (ie add, subtract, modus, multi..etc). So i have to ask the user to enter a number between 0 & 9 depending on what action they want. Now if they enter a 10 or anything else, I am suppose to terminate the whole program. How the hell do i make the program terminate? Do i use 'return 0;' during that function, or do i use another code?
sub prompt_phase {
my ( $ans, $subr );
print "\n--------------------------------\n";
print "Please select a phase to execute\n";
print "--------------------------------\n";
print "0. Run steps 1,2,3\n";
print "1. Generate the list of streams for Depot: $::depot\n";
print "2. Examine the contents of each stream\n";
print "3. Scan the stream contents for evil twins\n";
print "Q. Exit\n";
print "\n";
print "Enter Selection: ";
$ans = <STDIN>;
chomp($ans);
exit 0 if ( $ans =~ m/q/i ) || ( $ans =~ m/x/i ) || ( $ans eq "" );
if ( !( ( ( $ans >= 0 ) && ( $ans <= 3 ) ) ) )
{
print "\n\007$ans is not a valid selection\n\n";
return;
}
$subr = "phase_" . $ans;
no strict "refs";
&$subr();
use strict "refs";
}
Trending Topics
LS1 Tech Stories
The Best V8 Stories One Small Block at Time
6 Common C5 Corvette Failures and What's Involved In Repairing Them
Pouria Savadkouei
Retro Modern Bandit Pontiac Trans AM Comes With Burt Reynolds' Autograph
Verdad Gallardo
Top 10 Greatest Cadillac V Series Performance Models Ever, Ranked
Pouria Savadkouei
Top 10 Most Powerful Chevy Trucks Ever Made!
Hennessey's New Supercharged Silverado ZR2 Has 700 HP
Verdad Gallardo
Coachbuilt N2A Anteros Is an LS2-Powered C6 Corvette In Italian Clothes
Verdad Gallardo
Awesome K5 Blazer Restomod Comes With C7 Corvette Power
Verdad Gallardo
10 Camaros You Should Never Buy
10 LS Engine Myths That Refuse to Die
Verdad Gallardo
TECH Fanatic
iTrader: (2)
Joined: Mar 2002
Posts: 1,195
Likes: 0
From: I can drive my F-body in Winter!
1) print out user options
2) read for user input (using an individual char)
3) determine whether a character is a digit (use "isdigit(insert_variable_here)" (include ctype.h) when used it will return 0 (false) if the character is not a digit and 1 (true) if it is....so an ex: "if (isdigit(c)" ... in addtion you need to also check for the letter Q . so a combined statement such as [i]if((isdigit(c)) || ((c == 'q') || (c == 'Q')))if it isn't the input you need,you can clear the scree, and redisplay the options or an error statement or a combination of both.
4) once it is, and bad inputs filtered out, perform a switch statement within the if statement for each option accordingly
2) read for user input (using an individual char)
3) determine whether a character is a digit (use "isdigit(insert_variable_here)" (include ctype.h) when used it will return 0 (false) if the character is not a digit and 1 (true) if it is....so an ex: "if (isdigit(c)" ... in addtion you need to also check for the letter Q . so a combined statement such as [i]if((isdigit(c)) || ((c == 'q') || (c == 'Q')))if it isn't the input you need,you can clear the scree, and redisplay the options or an error statement or a combination of both.
4) once it is, and bad inputs filtered out, perform a switch statement within the if statement for each option accordingly
Last edited by Rhode Island Red; Oct 19, 2005 at 01:06 PM.
okay that helps. I am also not sure on a void function. I know I have to use this function to print out a menu of options to choose from. It is supposed to display something like this to the user (this is shortened):
'accumulator=0
1) Enter number
2) Add
3) Subtract
4) Mutliply
Please enter a number from 0 to 9:'
How exactly would i use a void function to display this to the screen?
'accumulator=0
1) Enter number
2) Add
3) Subtract
4) Mutliply
Please enter a number from 0 to 9:'
How exactly would i use a void function to display this to the screen?
TECH Fanatic
iTrader: (2)
Joined: Mar 2002
Posts: 1,195
Likes: 0
From: I can drive my F-body in Winter!
void display_the_menu (void)
{
cout << "1) Enter Number \n"; //or printf("1) Enter Number \n");
.
.
.
}
you use a void only when you expect the function to return nothing
in your main procedure, call this function, then read the char, then call the processing function and pass it the character (by value) . and go from there
{
cout << "1) Enter Number \n"; //or printf("1) Enter Number \n");
.
.
.
}
you use a void only when you expect the function to return nothing
in your main procedure, call this function, then read the char, then call the processing function and pass it the character (by value) . and go from there
Last edited by Rhode Island Red; Oct 19, 2005 at 01:17 PM.
i get so confused on this stuff. That makes sense but when you say you don't want it to return anything, does that mean it just goes on to the next function or loop that is next?
TECH Fanatic
iTrader: (2)
Joined: Mar 2002
Posts: 1,195
Likes: 0
From: I can drive my F-body in Winter!
Originally Posted by lilstephsls1
i get so confused on this stuff. That makes sense but when you say you don't want it to return anything, does that mean it just goes on to the next function or loop that is next?
i am trying hard. I just suck at this ****.
okay i am trying to run the program just but i am coming up with errors regarding my 'display_menu'. Where the hell do I declare that??
. THis is what my program looks like so far:
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main ()
{
//declare and initialize objects
double accumulator(0);
char display_menu;
//ask the user to enter a number that will be the accumulator
cout << "Enter a number ";
cin >> accumulator;
void display_menu()
{
cout << accumulator;
cout << "1) Enter Number \n";
cout << "2) Add \n";
cout << "3) Subtract \n";
cout << "4) Multiply \n";
cout << "5) Divide \n";
cout << "6) Modulus \n";
cout << "7) Raise to power \n";
cout << "8) Square root \n";
cout << "9) Negate \n";
cout << "0) Exit \n";
cout << "Please enter a number from 0 to 9 \n";
return;
}
return 0;
}
okay i am trying to run the program just but i am coming up with errors regarding my 'display_menu'. Where the hell do I declare that??
. THis is what my program looks like so far: #include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main ()
{
//declare and initialize objects
double accumulator(0);
char display_menu;
//ask the user to enter a number that will be the accumulator
cout << "Enter a number ";
cin >> accumulator;
void display_menu()
{
cout << accumulator;
cout << "1) Enter Number \n";
cout << "2) Add \n";
cout << "3) Subtract \n";
cout << "4) Multiply \n";
cout << "5) Divide \n";
cout << "6) Modulus \n";
cout << "7) Raise to power \n";
cout << "8) Square root \n";
cout << "9) Negate \n";
cout << "0) Exit \n";
cout << "Please enter a number from 0 to 9 \n";
return;
}
return 0;
}
TECH Fanatic
iTrader: (2)
Joined: Mar 2002
Posts: 1,195
Likes: 0
From: I can drive my F-body in Winter!
move the display function outside (and above - traditionally) the main procedure. C++ likes independent procedures. No need to have functions declared within functions with this one.
hint: usually you can trace an obscure error to the earliest line in the program, you understand,if the error is not so obvious. An coding error can create following errors as a result, that are actually not code errors, but the compiler unable to properly interpret the rest of the code after the error (usually syntax errors)
oh , and remove the "\n" and add ": " instead at the readline. People are used to entering at the line commanded, unless the command is quite long
hint: usually you can trace an obscure error to the earliest line in the program, you understand,if the error is not so obvious. An coding error can create following errors as a result, that are actually not code errors, but the compiler unable to properly interpret the rest of the code after the error (usually syntax errors)
oh , and remove the "\n" and add ": " instead at the readline. People are used to entering at the line commanded, unless the command is quite long
thank you so much cheese. i got it to work finally. For some reason i thought i could put the void and double functions inside the main function, which caused me to have about a million errors and freak out. After all that shananagans, the rest was pretty simple. I had to use a switch statement to give me the calculations and whatnot. That stuff seems pretty easy. Thanks for your help again!