**RCC Twin Turbo Build Update**
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**RCC Twin Turbo Build Update**
Finally some parts are starting to roll in so Josh began the new build. I will try and keep the pics coming weekly for you to view RC. Please let me know what yall think.
Updated pics from yesterday:
Updated pics from yesterday:
#6
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amazing build, do you happen to have a flow chart for your oval pipe. Ive been curious for a long time about flow characteristics. I know its the cross sectional area that matters. But cant ever seem to find a flow chart for oval pipe. Have them all day for round, just not oval
And you guys are killing me. Making me wanna go live in a box so i can afford to make my car this sick. lol Great work, as always!!!!!!!
And you guys are killing me. Making me wanna go live in a box so i can afford to make my car this sick. lol Great work, as always!!!!!!!
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#8
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amazing build, do you happen to have a flow chart for your oval pipe. Ive been curious for a long time about flow characteristics. I know its the cross sectional area that matters. But cant ever seem to find a flow chart for oval pipe. Have them all day for round, just not oval
And you guys are killing me. Making me wanna go live in a box so i can afford to make my car this sick. lol Great work, as always!!!!!!!
And you guys are killing me. Making me wanna go live in a box so i can afford to make my car this sick. lol Great work, as always!!!!!!!
Spintech sells everything!!! Up to a 6in Oval.
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Im not saying your method is flawed. It would help to know what the flow of the oval pipe is. IE. Pressure drop/friction loss. Since i dont have a chart i cannot tell you. other information to know would be, the velocity in which your exhaust is moving.
But i cant tell you that a 5" pipe that is flowing 100 cfm has a friction loss of .2 and that a 10" pipe flowing 100 cfm has a friction loss of around .05 which is much better. Now i used 5" and 10" at 100 cfm because it was round numbers.
but the same does and will hold true for smaller size pipes. Now, If i had an oval chart, i could figure out what size it would take to be equivalent.
maybe ill try this formula on for size. lol
de = 1.55 (π b2 / 4 + a b - b2)0.625/(π b + 2 a - 2 b)0.25
http://www.engineeringtoolbox.com/eq...ter-d_205.html
Found at bottom of page, last equation.
give me a second, and ill figure this out. lol
But i cant tell you that a 5" pipe that is flowing 100 cfm has a friction loss of .2 and that a 10" pipe flowing 100 cfm has a friction loss of around .05 which is much better. Now i used 5" and 10" at 100 cfm because it was round numbers.
but the same does and will hold true for smaller size pipes. Now, If i had an oval chart, i could figure out what size it would take to be equivalent.
maybe ill try this formula on for size. lol
de = 1.55 (π b2 / 4 + a b - b2)0.625/(π b + 2 a - 2 b)0.25
http://www.engineeringtoolbox.com/eq...ter-d_205.html
Found at bottom of page, last equation.
give me a second, and ill figure this out. lol
Last edited by JAX04; 07-22-2010 at 01:23 PM.
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Now unless i completely botched that formula and the math. Your 5" oval is about the same as a 4.25" diameter Round pipe. Assuming the flow characteristics are similar. Which i have not determined yet.
assuming that 3.25=B and 6=A which is the numbers used from spintechs' drawing. Height and Width.
Im no math wizz, and haven't done a compound math problem in over 10 years. i hope i did it right
Im going to do it again, probably two more times, it was fun. Not having even looked at an equation like that in years. lol
EDIT: Did it again, and did it somewhat differently, i thought i made a previous mistake, and still got 4.247
assuming that 3.25=B and 6=A which is the numbers used from spintechs' drawing. Height and Width.
Im no math wizz, and haven't done a compound math problem in over 10 years. i hope i did it right
Im going to do it again, probably two more times, it was fun. Not having even looked at an equation like that in years. lol
EDIT: Did it again, and did it somewhat differently, i thought i made a previous mistake, and still got 4.247
Last edited by JAX04; 07-22-2010 at 02:10 PM.
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right on, good move. It must keep equal hydraulic radius in order to not affect flow. Its not as simple as equal areas because of friction losses of the fluid against the walls of the tubing as well as friction between the fluid itself, although this maybe negligible in some cases.
#17
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right on, good move. It must keep equal hydraulic radius in order to not affect flow. Its not as simple as equal areas because of friction losses of the fluid against the walls of the tubing as well as friction between the fluid itself, although this maybe negligible in some cases.
higher head pressure would result in a higher reynolds number. And a lower pressure drop would result in a more laminar flow
still trying to find the formula for hydraulic radius of oval tubing
Either way, going from two pipes of a diameter of 3.5" to a single 5" oval will result in a higher pressure at that point and cause a more turbulent flow. Which is not what we want.
Last edited by JAX04; 07-22-2010 at 03:13 PM.