32lb injectors
32lb injectors how much rwhp can 32lb injectors go before maxed out.Lets say youre an A4 with heads and cam doing 390 400 rwhp.How big of a dry shot can you go before it will be maxed out
Originally Posted by Robert56@NitrousDirect
I have answered this question more than a couple times lately, including the math. 
Robert
Robert
Originally Posted by Z284U2TRY
I would say those injectors max would make 500 wheel. Not sugested but it's been done depending on fuel fuel psi those are rated at.
john
Ok John, sorry I was kinda busy before. Here is the math to get a good idea of what you need.
(Projected BHP x .5) / 6.4 = min inject to meet the 80% rule
So lets say you have 400rwhp as suggested. We now need to convert this to crank hp (bhp). 400 plus 15% drive train lose equals 460bhp. Now lets add a 125 shot to that for a starting point of 525hp.
So.
525 x .5 = 262.5
262.5 / 6.4 = 41.01 min injector
Now you can punch in any figure you want. Also going over 80% really is not a concern when just a short 1/4 mile pass, as this is a wear/tear saver. Just stay away from going static or 100%. Hope this helps.
Robert
(Projected BHP x .5) / 6.4 = min inject to meet the 80% rule
So lets say you have 400rwhp as suggested. We now need to convert this to crank hp (bhp). 400 plus 15% drive train lose equals 460bhp. Now lets add a 125 shot to that for a starting point of 525hp.
So.
525 x .5 = 262.5
262.5 / 6.4 = 41.01 min injector
Now you can punch in any figure you want. Also going over 80% really is not a concern when just a short 1/4 mile pass, as this is a wear/tear saver. Just stay away from going static or 100%. Hope this helps.
Robert
Originally Posted by Robert56@NitrousDirect
Ok John, sorry I was kinda busy before. Here is the math to get a good idea of what you need.
(Projected BHP x .5) / 6.4 = min inject to meet the 80% rule
So lets say you have 400rwhp as suggested. We now need to convert this to crank hp (bhp). 400 plus 15% drive train lose equals 460bhp. Now lets add a 125 shot to that for a starting point of 525hp.
So.
525 x .5 = 262.5
262.5 / 6.4 = 41.01 min injector
Now you can punch in any figure you want. Also going over 80% really is not a concern when just a short 1/4 mile pass, as this is a wear/tear saver. Just stay away from going static or 100%. Hope this helps.
Robert
(Projected BHP x .5) / 6.4 = min inject to meet the 80% rule
So lets say you have 400rwhp as suggested. We now need to convert this to crank hp (bhp). 400 plus 15% drive train lose equals 460bhp. Now lets add a 125 shot to that for a starting point of 525hp.
So.
525 x .5 = 262.5
262.5 / 6.4 = 41.01 min injector
Now you can punch in any figure you want. Also going over 80% really is not a concern when just a short 1/4 mile pass, as this is a wear/tear saver. Just stay away from going static or 100%. Hope this helps.
Robert
Trending Topics
Originally Posted by Robert56@NitrousDirect
(Projected BHP x .5) / 6.4 = min inject to meet the 80% rule
So lets say you have 400rwhp as suggested. We now need to convert this to crank hp (bhp). 400 plus 15% drive train lose equals 460bhp. Now lets add a 125 shot to that for a starting point of 525hp.
So.
525 x .5 = 262.5
262.5 / 6.4 = 41.01 min injector
Robert
So lets say you have 400rwhp as suggested. We now need to convert this to crank hp (bhp). 400 plus 15% drive train lose equals 460bhp. Now lets add a 125 shot to that for a starting point of 525hp.
So.
525 x .5 = 262.5
262.5 / 6.4 = 41.01 min injector
Robert
"Projected flywheel HP x .5) / 6.4 = min inj to meet 80% DC rule
So we first need to turn your projected hp into BHP. We just subtract 15% from your anticipated 385rwhp + 100rwhp shot = 485rwhp.
485 - 15% = 412.25bhp
412 x .5 = 206
206 / 6.4 = 32.18 injector to meet the 80% duty cycle rule.
Robert
In your first example, you are subtracting 15% from BHP and adding a full N2o shot, whereas in the second post you're subtracting 15% from the TOTAL.
I know, not much difference, just keeping you on your toes.
Also, how is the 6.4 figured? I'm going to put Beer's 28s in today and want to put the 150 shot back in. I know I'll be hitting the mid 90s (dc) again but I'm ok with it since I hardly ever run it for a full 1/4 mile. (I'm usually ahead by then and shut down, if not.. no reason to stay on it)
LS1 Tech Stories
The Best V8 Stories One Small Block at Time
6 Common C5 Corvette Failures and What's Involved In Repairing Them
Pouria Savadkouei
Retro Modern Bandit Pontiac Trans AM Comes With Burt Reynolds' Autograph
Verdad Gallardo
Top 10 Greatest Cadillac V Series Performance Models Ever, Ranked
Pouria Savadkouei
Top 10 Most Powerful Chevy Trucks Ever Made!
Hennessey's New Supercharged Silverado ZR2 Has 700 HP
Verdad Gallardo
Coachbuilt N2A Anteros Is an LS2-Powered C6 Corvette In Italian Clothes
Verdad Gallardo
Awesome K5 Blazer Restomod Comes With C7 Corvette Power
Verdad Gallardo
10 Camaros You Should Never Buy
10 LS Engine Myths That Refuse to Die
Verdad Gallardo
Originally Posted by Todd157k
This isn't exactly the way you've posted it before (loyal subject that I am..LOL). Your previous post:
"Projected flywheel HP x .5) / 6.4 = min inj to meet 80% DC rule
So we first need to turn your projected hp into BHP. We just subtract 15% from your anticipated 385rwhp + 100rwhp shot = 485rwhp.
485 - 15% = 412.25bhp
412 x .5 = 206
206 / 6.4 = 32.18 injector to meet the 80% duty cycle rule.
Robert
In your first example, you are subtracting 15% from BHP and adding a full N2o shot, whereas in the second post you're subtracting 15% from the TOTAL.
I know, not much difference, just keeping you on your toes.
Also, how is the 6.4 figured? I'm going to put Beer's 28s in today and want to put the 150 shot back in. I know I'll be hitting the mid 90s (dc) again but I'm ok with it since I hardly ever run it for a full 1/4 mile. (I'm usually ahead by then and shut down, if not.. no reason to stay on it)
"Projected flywheel HP x .5) / 6.4 = min inj to meet 80% DC rule
So we first need to turn your projected hp into BHP. We just subtract 15% from your anticipated 385rwhp + 100rwhp shot = 485rwhp.
485 - 15% = 412.25bhp
412 x .5 = 206
206 / 6.4 = 32.18 injector to meet the 80% duty cycle rule.
Robert
In your first example, you are subtracting 15% from BHP and adding a full N2o shot, whereas in the second post you're subtracting 15% from the TOTAL.
I know, not much difference, just keeping you on your toes.
Also, how is the 6.4 figured? I'm going to put Beer's 28s in today and want to put the 150 shot back in. I know I'll be hitting the mid 90s (dc) again but I'm ok with it since I hardly ever run it for a full 1/4 mile. (I'm usually ahead by then and shut down, if not.. no reason to stay on it)
The 6.4 is a common denom for 8 cyl motors. Here's the full equation.
(bhp x bsfc) / (No. of Injectors x Duty Cycle .8) = injector
bsfc is the break specific fuel consumption, .5 is normally used except blower/turbos use .6
You can also punch in any DC you like and figure things out from there.
Robert
