2005-2012 GM LS2/LS7/LS3 Cars Coil-Near-Plug Conn Kit
08-22-2012, 04:12 PM
#1
2005-2012 GM LS2/LS7/LS3 Cars Coil-Near-Plug Conn Kit 
$130
Direct OEM replacement, exceeds OEM specifications, OBD-II computer safe
Increase power to the spark plug up to 400% over stock
Customers have reported up to 15HP (normally aspirated) & 35HP (s/c, turbo, & nitrous). Average gains on an otherwise stock motor are 5hp N/A and 12 to 15 with factory forced induction
0 Ohm resistance, no RFI / EMI interference thanks to patented protector ring
Patented* design works with all fuel injection systems, street cars and race cars
Solid stainless connector cable with stainless snap lock spark plug connectors
High temperature silicone boots, 8MM jacket with fiberglass-reinforced braid resists temperatures up to 500 degrees f (1200 degree f. boots optional).
Ideal for use with aftermarket headers and/or turbocharger systems
Includes all necessary hardware
Over 600 fitments!
* Granatelli O ohm wires are patent protected by United States Patent number 7,185,622. This patent covers our unique method of producing ignition wires of extremely low resistance while maintaining very high noise suppression. The benefit of this invention is that full electrical energy from the ignition source is transmitted to the spark plug. The end result of the application of this method is increased horsepower, torque and fuel economy.
Last edited by granatelli sales; 10-24-2012 at 01:14 PM.
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09-14-2012, 01:25 PM
#12
If you have headers we would recommend our hi temp wires or even the double wrap below
Last edited by granatelli sales; 10-24-2012 at 01:15 PM.
09-14-2012, 02:47 PM
#13
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What a bunch of BS.
JR, you should be ashamed.
V= IR V= Voltage, I = Current, R = Resistance...ie...Ohms.
If you don't have any currant or voltage running through the wire, of course resistance (ohms) is going to be zero. Now, hook up your wire and run the test again.
You can fool some of the people some times, but you're not going to fool anyone with a high school level of knowledge on electronics and considering my background in electronics, I'm calling you out.
JR, you should be ashamed.
V= IR V= Voltage, I = Current, R = Resistance...ie...Ohms.
If you don't have any currant or voltage running through the wire, of course resistance (ohms) is going to be zero. Now, hook up your wire and run the test again.
You can fool some of the people some times, but you're not going to fool anyone with a high school level of knowledge on electronics and considering my background in electronics, I'm calling you out.
Last edited by DarkblueTA; 09-14-2012 at 02:59 PM.
09-14-2012, 03:41 PM
#14
What a bunch of BS.
JR, you should be ashamed.
V= IR V= Voltage, I = Current, R = Resistance...ie...Ohms.
If you don't have any currant or voltage running through the wire, of course resistance (ohms) is going to be zero. Now, hook up your wire and run the test again.
You can fool some of the people some times, but you're not going to fool anyone with a high school level of knowledge on electronics and considering my background in electronics, I'm calling you out.
JR, you should be ashamed.
V= IR V= Voltage, I = Current, R = Resistance...ie...Ohms.
If you don't have any currant or voltage running through the wire, of course resistance (ohms) is going to be zero. Now, hook up your wire and run the test again.
You can fool some of the people some times, but you're not going to fool anyone with a high school level of knowledge on electronics and considering my background in electronics, I'm calling you out.
The stock wires have roughly a 900 ohm drop and the Granatelli wires are 0 (zero) - That is were the gains come from
09-14-2012, 06:06 PM
#16
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Any wire, that has electricity flowing through it will never have zero ohms. This is flat out impossible. It is both physically and mathematically impossible to not have resistance in a circuit, no matter what the circuit is. Hency why I referenced the formula of V = IR. (If you want to solve for resistance, it would V/I=R). The only way to not have ohms in a circuit is to have an open circuit (ie...no electricity flows through it).
I have seen a bunch of fluff posted by JR already on this site, (just look at the forced induction section, he doesn't even know what a/r housing he uses on "his" turbo kit
) and other sites. Don't worry, sooner or later someone would have called him out on this tech board like the mustang boards he loves so dearly. Have a good night/weekend.
09-14-2012, 06:13 PM
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09-14-2012, 06:29 PM
#18
He knows what A/R is on Granatelli Motor Sports Twin Turbo System
I'm the one who didn't answer the question so... and the wire are ZERO Ohm (Ω)
We had a Custom 25 foot wire that when around our PRI booth and still had ZERO Ohm (Ω)
http://youtu.be/ZNE800ZsiF4?t=3m58s
I'm the one who didn't answer the question so... and the wire are ZERO Ohm (Ω)
We had a Custom 25 foot wire that when around our PRI booth and still had ZERO Ohm (Ω)
http://youtu.be/ZNE800ZsiF4?t=3m58s
09-14-2012, 07:17 PM
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V= Voltage
I = Current (amps)
R = Resistance (ohms)
Name me any number multiplied by zero (the claim of zero ohms/resistance) that is going to allow voltage to be higher than zero. If you have zero resistance, you have zero current (I) which you have zero voltage. So no, there was no current flowing through the wire.
Don't care who says they have a zero ohm wire, it doesn't exsist.
The others show a reading because they're properly hooked up to complete the circuit. I also wonder why there is a nice little "iron ring" around JR's wires. Not that it would help making the wire zero ohms. Just the opposite really.