I have a basic mechanic question....
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Teching In
Joined: Aug 2009
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From: IRAQ/ Ft Riley, KS
I have a basic mechanic question.... I don't want to sound dumb but I have asked several peoplle this question. When a engine is a "5.7" liter or "5.0" what does the 5.7 stand for?? I have heard its the amount oil the crank case holds or the maximum amount of air a engine can hold. Can some one shine some light on me??
its pretty much the displacement of the engine. 5.7=346ci 6.0=400ci 5.0=302ci
its the volume covered by all the pistons on one stroke added up. thats the easiest way to explain it. the way you find it is by using the bore and stroke to figure out the ci.
its alot of math but its easy. so 1000CC=1 liter and you convert it to CI and figure it out from there. it has nothing to do with the oil
its the volume covered by all the pistons on one stroke added up. thats the easiest way to explain it. the way you find it is by using the bore and stroke to figure out the ci.
its alot of math but its easy. so 1000CC=1 liter and you convert it to CI and figure it out from there. it has nothing to do with the oil
its pretty much the displacement of the engine. 5.7=346ci 6.0=400ci 5.0=302ci
its the volume covered by all the pistons on one stroke added up. thats the easiest way to explain it. the way you find it is by using the bore and stroke to figure out the ci.
its alot of math but its easy. so 1000CC=1 liter and you convert it to CI and figure it out from there. it has nothing to do with the oil
its the volume covered by all the pistons on one stroke added up. thats the easiest way to explain it. the way you find it is by using the bore and stroke to figure out the ci.
its alot of math but its easy. so 1000CC=1 liter and you convert it to CI and figure it out from there. it has nothing to do with the oil
6.6L is a 400 cubic inch.
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364ci..
6.6l can be a 400 Small Block, 402 LS Stroker.. and probably a couple of others.
Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.
6.6l can be a 400 Small Block, 402 LS Stroker.. and probably a couple of others.
Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.
Its really means that every complete turn of the crankshaft the engines displaces 5.7L or 346 cubic inches of space. That means the pistons move or displace that amount of space. What comes next is that space is filled with an air-fuel mixture and compressed then ignited forcing the pistons down causing the crankshaft to rotate.
[/QUOTE]
Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.[/QUOTE]
yeah, but those damn douchers at ford cheater with their 5.0.
sissy 4.9s!
Pretty much it's what the amount of cc's round close to. My 408 is a 6.7l, but is actually 6685.92cc.[/QUOTE]
yeah, but those damn douchers at ford cheater with their 5.0.
sissy 4.9s! 
In case you were curious where everyone is coming up with their displacements, its just simple math. Find the area of an individual cylinder...pi X (radius squared) X height, or in gearhead speak 3.14 X (1/2 of bore squared) X stroke. Take this number x the number of cylinders (eight if your a real man) and you have displacement. Example: engine with bore of 3.9 and stroke of 3.62.
3.14 X [(0.5 X 3.9)(0.5 X 3.9)] X 3.62 = 43.22
43.22 X 8 = 345.78, rounded to 346 = LS1
To get the displacement in metric, just use measurements in centimeters for bore and stroke.
3.14 X [(0.5 X 3.9)(0.5 X 3.9)] X 3.62 = 43.22
43.22 X 8 = 345.78, rounded to 346 = LS1
To get the displacement in metric, just use measurements in centimeters for bore and stroke.
