Short tq arm...Pinion angle question
#1
Short tq arm...Pinion angle question
I'm about to put a short style tq arm in the car, in hopes it will help out my launches a little better vs the Long style one. My question is, when i set up the pinion angle where would be a good starting point for it? is -2* too much? Car is a full weight (37xx raceweight) M6 car. QA1's w/coilover, 9" with spohn ARB, 28x11.5x15 Hoosier QTP's. The car has solid links on everything accept the forward mount of the TA.
Last edited by WheelsUp84z; 08-06-2011 at 01:02 AM.
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#9
this is the way I see it.
you want the arm to be in line under acceleration. In other words you want the arm to travel upwards by a distance that will allow for the driveshaft to be in line with the pinion and the output shaft of the transmission.
When a short arm travels 2 degrees it travels a shorter distance (ark distance)
compared to:
When a long arm travels 2 degrees it travels a longer distance (ark distance)
2 degrees is 1/180th of a revolution.
Therefore, it seems a short arm will need more pre-set (measured in degrees) at rest than a long arm, all else constant. However, a short arm is located further to the rear of the chassis where the magnitude of chassis movement is different than that compared to any point forward. Compare the distance in magnitude of chassis movement rear to forward to the difference in vertial movement of the short vs. long arm. Negate any difference by adjusting the pinion angle.
Any change in slope of the LCA would change the magnitude of chassis movement.
A solid chassis mount on a torque arm will allow less room for error.
you want the arm to be in line under acceleration. In other words you want the arm to travel upwards by a distance that will allow for the driveshaft to be in line with the pinion and the output shaft of the transmission.
When a short arm travels 2 degrees it travels a shorter distance (ark distance)
compared to:
When a long arm travels 2 degrees it travels a longer distance (ark distance)
2 degrees is 1/180th of a revolution.
Therefore, it seems a short arm will need more pre-set (measured in degrees) at rest than a long arm, all else constant. However, a short arm is located further to the rear of the chassis where the magnitude of chassis movement is different than that compared to any point forward. Compare the distance in magnitude of chassis movement rear to forward to the difference in vertial movement of the short vs. long arm. Negate any difference by adjusting the pinion angle.
Any change in slope of the LCA would change the magnitude of chassis movement.
A solid chassis mount on a torque arm will allow less room for error.
Last edited by tee-boy; 08-09-2011 at 12:29 PM.
#11
this is the way I see it.
you want the arm to be in line under acceleration. In other words you want the arm to travel upwards by a distance that will allow for the driveshaft to be in line with the pinion and the output shaft of the transmission.
When a short arm travels 2 degrees it travels a shorter distance (ark distance)
compared to:
When a long arm travels 2 degrees it travels a longer distance (ark distance)
2 degrees is 1/180th of a revolution.
Therefore, it seems a short arm will need more pre-set (measured in degrees) at rest than a long arm, all else constant. However, a short arm is located further to the rear of the chassis where the magnitude of chassis movement is different than that compared to any point forward. Compare the distance in magnitude of chassis movement rear to forward to the difference in vertial movement of the short vs. long arm. Negate any difference by adjusting the pinion angle.
Any change in slope of the LCA would change the magnitude of chassis movement.
A solid chassis mount on a torque arm will allow less room for error.
you want the arm to be in line under acceleration. In other words you want the arm to travel upwards by a distance that will allow for the driveshaft to be in line with the pinion and the output shaft of the transmission.
When a short arm travels 2 degrees it travels a shorter distance (ark distance)
compared to:
When a long arm travels 2 degrees it travels a longer distance (ark distance)
2 degrees is 1/180th of a revolution.
Therefore, it seems a short arm will need more pre-set (measured in degrees) at rest than a long arm, all else constant. However, a short arm is located further to the rear of the chassis where the magnitude of chassis movement is different than that compared to any point forward. Compare the distance in magnitude of chassis movement rear to forward to the difference in vertial movement of the short vs. long arm. Negate any difference by adjusting the pinion angle.
Any change in slope of the LCA would change the magnitude of chassis movement.
A solid chassis mount on a torque arm will allow less room for error.