Street Racing & Kill Stories Basic Technical Questions & Advice

Me Vs HOSS and WS6

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Old May 23, 2005 | 06:48 PM
  #61  
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If were so moronic, if were so dumb and not open minded like you. Why do you stay here if were such a lost cause? Maybe this isn't the place for you, a Evo forum would love this story I'm sure.

Just trying to be nice.
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Old May 23, 2005 | 07:19 PM
  #62  
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Originally Posted by EvilDylan
yeah i guess im lying.

i mean theres no way in hell it could ever happen. no matter what.

you're completely right. I just made all this up cause its so easy and fun frustrating morons like yourself.
Sounds like you're the one frustrated man. 10 cars does not make sense. I could see if you had a 10 second car and he was stock but you're not that much faster than a stock LS1. Something had to have happened. Plain and simple.

By the way, your first equation made no sense in comparing 2 cars.
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Old May 23, 2005 | 07:42 PM
  #63  
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yeah looking at my first equation, i dont really know exactly what i was thinking. but it made sense at the moment!

actually now that i think about it i was thinking im a full second faster through the 1/4 mile, but i accidentally used my 1/8 mile trap speed.
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Old May 24, 2005 | 12:51 AM
  #64  
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Originally Posted by EvilDylan
yeah looking at my first equation, i dont really know exactly what i was thinking. but it made sense at the moment!

actually now that i think about it i was thinking im a full second faster through the 1/4 mile, but i accidentally used my 1/8 mile trap speed.
You were still comparing a moving object with a still object. I guess it makes sense if you're racing a moron who can't drive and leaves it in park.
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Old May 24, 2005 | 05:23 AM
  #65  
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ohh, ooh, i have the answer to everyone's problem here....



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Old May 24, 2005 | 06:20 AM
  #66  
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Originally Posted by EvilDylan
Whats so funny? Do you know how to do math?

90 mph = 132 feet per second.

How long is a car? Id say on average about 10-12 feet

133/12 = 11

WOW so according to logic a 13 second car getting beat by a 12 second car would be losing by approximately 11 car lengths.

open mouth, insert foot there dal ***
Your math is assuming that the second car is traveling 0mph... throw in the speed of the other car and the distance closes alot.

open mouth, insert foot there dal *** (dal *** wtf is dal ***?)

anyway nice car and good kill
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Old May 24, 2005 | 07:24 AM
  #67  
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no, if i were assuming that the car were going 0 mph than i would be many many more carlenghts ahead. My assumption was that i was 1 second ahead of the other car. since i was traveling at 132 fps, and if iw ere 1 second ahead of a car, by the time the car had gotten to the same spot i was in when i was going 90 mph he would have traveled 133 feet. So i divided that by 12 feet for a car length should have been more like 15 feet.
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Old May 24, 2005 | 08:20 AM
  #68  
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Originally Posted by EvilDylan
Whats so funny? Do you know how to do math?

90 mph = 132 feet per second.

How long is a car? Id say on average about 10-12 feet

133/12 = 11

WOW so according to logic a 13 second car getting beat by a 12 second car would be losing by approximately 11 car lengths.

Hey guys, this equation is fine for an estimation, even though 10-12 feet is a little low for a car length (I guess you're talking mini coopers vs Caddy Devilles). It's a street race, everything is always approximate and exaggerated. That's just the way it is.

Nice kill. Now I need a H/C setup. This thread just cost me big $$$!!!!!
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Old May 24, 2005 | 08:30 AM
  #69  
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Congrats on your win.

wow, what a mess.

The average is about one tenth per car length. It varies when the cars run faster but it's a general average.

so he's about right, he said about 10 cars. He ran to about 120 mph, hence, he's quarter mile mph. I'd say he's made a good estimate.

Besides, just as one has posted, after around 5, I would of lost count, lol and it doesn't really matter.
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Old May 24, 2005 | 08:53 AM
  #70  
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Originally Posted by wickedwarlock
Congrats on your win.

wow, what a mess.

The average is about one tenth per car length. It varies when the cars run faster but it's a general average.

so he's about right, he said about 10 cars. He ran to about 120 mph, hence, he's quarter mile mph. I'd say he's made a good estimate.

Besides, just as one has posted, after around 5, I would of lost count, lol and it doesn't really matter.
He ran to the end of 3'rd which he stated he tops out before the 1/8th mile not a full quarter. I can see him putting 10 cars on a second slower car in the quarter.
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Old May 24, 2005 | 09:03 AM
  #71  
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Originally Posted by Dal1as
He ran to the end of 3'rd which he stated he tops out before the 1/8th mile not a full quarter. I can see him putting 10 cars on a second slower car in the quarter.
ah, good point. Well, that throws everything off.
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Old May 24, 2005 | 09:11 AM
  #72  
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Originally Posted by wickedwarlock
ah, good point. Well, that throws everything off.
i also said that it's possible i went farther than third. I raced a few times that night and the exact speed that i shut down is not exactly clear. Like i said though one thing is pretty clear and he was very very far back when i did shut down.
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Old May 24, 2005 | 09:27 AM
  #73  
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Originally Posted by EvilDylan
i also said that it's possible i went farther than third. I raced a few times that night and the exact speed that i shut down is not exactly clear. Like i said though one thing is pretty clear and he was very very far back when i did shut down.
Well then go back and edit your post and state that you went to the end of 4rth or a full quarter. 10 cars in the quarter on a car that is about a second slower is believable. 10 cars on practically anything in the 1/8th is not.
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Old May 24, 2005 | 02:12 PM
  #74  
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Distance in car lengths the 2 cars will be ...

1) From 0 mph to 90 mph (top of third).
2) A race from 40 mph to 110 mph (forth).


Car A (fbod) :

0 to 30 mph - 2.1 sec
0 to 60 mph - 5.0 sec
1/8 mile - 8.5 seconds @ 83 mph
1/4 mile - 13.1 seconds @ 108 mph

@ 60 ft - 1.9 secs
@ 330 ft - 6.0 secs
@ 1000 ft - 11.3 secs


Car B (evo) :

0 to 30 mph - 1.7 sec
0 to 60 mph - 4.5 sec
1/8 mile - 7.72 seconds @ 91 mph
1/4 mile - 12.1 seconds @ 117 mph

@ 60 ft - 1.6 secs
@ 330 ft - 5.1 secs
@ 1000 ft - 10.1 secs


Calculations:

Car A:

0 - 60 ft, average acceleration = 13.7 mph/sec
60 - 330 ft, average acceleration = 9.5 mph/sec
330 ft - 1/8 mile, average acceleration = 7.2 mph/sec
1/8 mile - 1000 ft, average acceleration = 5.6 mph/sec
1000 ft - 1/4 mile, average acceleration = 6.1 mph/sec


Car B:

0 - 60 ft, average acceleration = 15 mph/sec
60 - 330 ft, average acceleration = 13 mph/sec
330 ft - 1/8 mile, average acceleration = 5.51 mph/sec
1/8 mile - 1000 ft, average acceleration = 5.3 mph/sec
1000 ft - 1/4 mile, average acceleration = 4.5 mph/sec


Keep in mind.

1/4 Mile = 1,320 ft.
1/8 Mile = 660 ft
Car length = 16 ft.
.
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Old May 24, 2005 | 02:22 PM
  #75  
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.
First ... the cars are not standing still, they are moving.

Second... they are not traveling a constant 90mph, they are accelarating. As you can see by my calculations, the evo out accelerates the f-bod in the dig, which is it's quickest point (makes sense), and the f-bod out accelarates it up top (makes sense). If you look at that as a rough estimate, you see that starting from a 40mph roll would be a significant disadvantage to the evo.

Third ... they never went a full quarter-mile, so the 1 length per tenth is off .... not to mention that difference is generally quoted for mid 13 second cars ... as you get faster cars that will change some.

Forth ... we're talking about a roll race from 40-110 or so ... and a dig to the end of third, which is BEFORE the eight-mile mark (~90mph).
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Old May 24, 2005 | 03:56 PM
  #76  
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Those are some serious calculations.
Question with the numbers, why do the accels decrease, increase then decrease? I would think you would see then decrease more evenly.

Also, do you intergrate 2 times to find the accel equations, find begining and end accels then take the average? I haven't done this in years I can't remember how to do it right.

Based on the two 1/4 mile runs, at the instant that the EVO goes throught the traps, what is the distance between the two cars?
This is the question you should try to prove. I know this wont prove how far ahead the EVO was during the actual race. I just want to know.
I think you will come up with something like 9 to 10 cars.
Let us know what you come up with.
Math can be fun, it all depends on how you apply it.

PS. not trying to be an a$$, I like figuring it out too.

Still, nice kill
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Old May 24, 2005 | 09:06 PM
  #77  
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LOL phantom, that is ALL screwed up.

You are telling me that according to this "equation" my evo is out accelerated on the back 1/8 mile by a STOCK SS?

so since the SS gained a very generous 25 mph and i gained 26 i was out accelerated?

so at the 60' my lead is .3 seconds, then at the 330' mark it's .9 seconds, then at the 1/8 mile mark its down to .6 seconds then all the sudden i get a burst of speed at the 1000' mark and my lead is back up to 1.2 seconds, then again my lead slows down and at the end im .9 seconds ahead again. LOL dude, come on you know that entire post is BS and makes no sense.

What do fbody's dyno stock on a dynojet? MAYBE close to 300? on a dynojet id dyno about 340, and with my car being lighter im STILL out accelerated even from a 40 mph roll. I guess whatever school you're attending teaches a different type of physics than the one I'm going to. But then again they also taught me how to spell fourth.

Last edited by EvilDylan; May 24, 2005 at 09:15 PM.
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Old May 24, 2005 | 09:15 PM
  #78  
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nyzze, it would be like this.

at the instant i go through the 1/8 mile trap i woul dbe traveling 91 mph. IF i were to maintain that exact speed for the duration of time it took for the car to catch up, .6 seconds would have elapsed. Since we dont know the exact time and speed the car was going when i went through the traps, and it's nearly impossible to tell without a seperate timing system we will have to use the other cars trap speed and time to determine the actual distance.

so .6 seconds elapses since ive crossed the line, and im maintaining a 91mph speed. i will have traveled an additional 80 feet by the time he crosses the line. this is found by:

91 mph times 5280 feet (1 mile)
all divided by 3600 (number of seconds in an hour) then multiply that by the elapsed time of 6 tenths of a second. Since we are using feet per second as the final velocity.

you get 80.

thats for the 1/8 mile, if it were a 1/4 mile and once again i maintained a 117 mph speed and drove on for another full second, i would have traveled an additional 170 feet.

This is the simplest way to do the equation since there are so many unknowns. ie..his actual speed when i crossed the finish line and his rate of acceleration.

hopefully this clears something up.
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Old May 24, 2005 | 10:49 PM
  #79  
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After reading this thread, and taking some aspirin from the resulting headache, all I have to say is:


"Well, My dad can beat up your dad!"
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Old May 24, 2005 | 10:58 PM
  #80  
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