Find the exact arc length of the parametric curve without eliminating the parameter.
09-10-2007, 09:42 PM
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Find the exact arc length of the parametric curve without eliminating the parameter.
5. y = x^(2/3) from x = 1 to x = 8.
L = definite integral from 1 to 8 with respect to x;
square root of [1 + ((2/3x^(1/3))^2]
= square root of [1 + ((4/9x^(2/3)]
= square root of [1 + ((4/9x^(-2/3)]
L = definite integral from 1 to 8 with respect to x;
square root of [1 + ((2/3x^(1/3))^2]
= square root of [1 + ((4/9x^(2/3)]
= square root of [1 + ((4/9x^(-2/3)]
13. x = e^t cos t, y = e^t sin t (0 less than or equal to t less than or equal to pi/2)
L = definite integral from 0 to pi/ with respect to t;
square root of [(e^t(cos t - sin t))^2 + ((e^t(cos t + sin t))^2]
= square root of [2((e^t)^2)]
L = definite integral from 0 to pi/ with respect to t;
square root of [(e^t(cos t - sin t))^2 + ((e^t(cos t + sin t))^2]
= square root of [2((e^t)^2)]
09-10-2007, 10:08 PM
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Originally Posted by will69camaro
As I sit here and do my homework and surf LS1tech, I wonder...Does anyone do their own work anymore?
LOL just giving you a hard time. Good luck
William
LOL just giving you a hard time. Good luck
William
The answer is 2. 
