5252 Rpm
05-16-2007 | 06:25 PM
#1
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5252 Rpm I've read numerous places, one of which being here on LS1Tech that TQ and HP should always cross at 5252 RPM due to the formula. However, many many times I don't see that happening. What gives?
I see it fairly often in turbo motors, which has me wondering if the 5252 RPM point is only a N/A thing, but I'm decently sure I've seen graphs where they don't cross there either, and the motor isn't FI of any sort.
I see it fairly often in turbo motors, which has me wondering if the 5252 RPM point is only a N/A thing, but I'm decently sure I've seen graphs where they don't cross there either, and the motor isn't FI of any sort.
05-16-2007 | 07:21 PM
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Originally Posted by Sharpe
I bet if you look closer at these graphs, the TQ and HP curves are on different vertical RPM lines or whatever you call them. Just a thought. I don't know much about it.
Gimme 15 minutes and I'll get one of the books out and look at it and post back.
EDIT: Nope, y'all are absolutely right. Though there are quite a few odd graphs in this old turbo buick book nonetheless. Take a look at this one (it's from before computers!
):
Tuned odd? It fluctuates quite a bit, looks more like waves than a dyno to me.
, but it jumped out at me anyways. Last edited by RicoL; 05-16-2007 at 07:49 PM.
05-16-2007 | 07:36 PM
#5
LOL i cant remember for sure the formula but 5252 is in the formula for converting TQ to HP basicaly think of this HP is a porduct of TQ over time the faster work can be done with the same amount of TQ the more HP can be made. since 5252 is in the mathmatical equation it is the constant. so think of the RPM as time under 5253 more WORK(TQ) can be done than there is time for..... over 5252 less WORK (TQ) can be done but there is plenty of time to do it. 5252 in the equation means that it is the constant 5252=1 at that time the most work can be done at that time.
now a force induced or nitrous can can provide more work in that time period so it is not under the same constraint.
hope this kinda helps
found it
HP = (Torque * RPM) / 5252
found it here
http://www.car-videos.net/articles/h...wer_torque.asp
now a force induced or nitrous can can provide more work in that time period so it is not under the same constraint.
hope this kinda helps
found it
HP = (Torque * RPM) / 5252
found it here
http://www.car-videos.net/articles/h...wer_torque.asp
Last edited by camarokid94; 05-16-2007 at 07:42 PM.
05-16-2007 | 07:45 PM
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Originally Posted by camarokid94
LOL i cant remember for sure the formula but 5252 is in the formula for converting TQ to HP basicaly think of this HP is a porduct of TQ over time the faster work can be done with the same amount of TQ the more HP can be made. since 5252 is in the mathmatical equation it is the constant. so think of the RPM as time under 5253 more WORK(TQ) can be done than there is time for..... over 5252 less WORK (TQ) can be done but there is plenty of time to do it. 5252 in the equation means that it is the constant 5252=1 at that time the most work can be done at that time.
now a force induced or nitrous can can provide more work in that time period so it is not under the same constraint.
hope this kinda helps
now a force induced or nitrous can can provide more work in that time period so it is not under the same constraint.
hope this kinda helps
